(20 + x)-3
Three less than twice x is 2x-3.Two more than the quantity 3 times x is 3x + 2.The product of these is (2x-3)(3x+2), which can also be written as:(6x2 - 5x - 6)
I think so but im not sure
let x be a number then the eqution becomes x-3
7cos(x)=3sin(x) 7=3[sin(x)/cos(x)] 7=3tan(x) 7/3=tan(x) x=66.8, 246.8
3-X
x > 1
(x - 24) is 24 less than x, then multiply this quantity by 3: 3*(x-24) or 3x - 72
x is less than or equal to 15
That factors to (x - 6)(x + 3) x is less than or equal to -3, 6
The result of the equation 6x -3 less than 3 is X < 1.
Let the number be x Then its square is x^2 3 less than the square of a number is x^2-3 (or x square minus three)
x + 3 < 5
x is equal to or less than -3 means that x is every number from -3 onwards all the way to negative infinity. For example, -4 would be less than -3, -5 would be less than -4 which is less than -3 and so forth. So for the final answer, the interval of x that is equal to or less than -3 would be written like this: (-inf,-3] There is a parenthesis on negative infinity because it is impossible to reach infinity and since x is equal to -3, we put the brackets to indicate that the -3 is included in the interval.
(20 + x)-3
x is less than or equal to negative 3 or x< or =-3
X-3?