(20 + x)-3
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The problem is incomplete as you wrote it. There needs to be a part in the problem where they tell you what 3 less than the quotient of number and 5 is equal to.The question as you wrote it is expressed as:(x/5)-3To solve for "x" you need to know what the equation is equal to.Example :If 3 less than the quotient of number and 5 is equal to (for example) 10, the equation will be expressed as:(x/5)-3= 10Adding 3 to each side of the equal sign produces x/5 = 13To get the "x" by-itself, you need to multiply both side of the equal sign by 5.(x/5)(5)=13(5)x = 65
The answer is 10. 3 x 10 = 30 30 - 10 = 20
2n/6 - 9 or n/3 - 9
The numbers 1, 2, 3, ... , 18, 19.
That is simply not true. For example, consider the quotient of 2/9 and 2/3.(2/9) / (2/3) = (2*3)/(9*2) = 3/9 = 1/3 which, unless I am very much mistaken, is not greater than one of the fractions: namely 2/3.