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if you're solving for x,
3x-y >= 5
3x >= 5+y
x >= (5+y)/3
solving for y,
3x-y >= 5
-y >= 5-3x
y <= -5+3x or 3x-5 (note that the symbollogy changed when multiplying both sides by a negative number)
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If you mean x2-3x+5 then the answer is none because its discriminant is less than zero
Oh, dude, it's like you're asking me to do math at a party. Okay, so "thrice a number" is just 3 times a number, and "five less than" means you subtract 5. So, the algebraic expression for "five less than thrice a number" would be 3x - 5. Easy peasy, right?
3x^5 If these are 5 of 3x multiplied together the it must be (3x)^5 =3^5 times x^5
well what does it equal to find out