The number of diagonals for a shape with x sides is (x²-3x)/2
The number of sides is x
You want to know if x is ever less than (x²-3x)/2 or else (x²-3x)/2 - x > 0
(x² - 3x) / 2 - x > 0
(x² - 3x)/2 - (2x)/x > 0
x² - 3x - 2x > 0
x² - 5x > 0
x(x-5)>0
This only true if x<0 or x>5, and since a polygon cannot have less than 2 sides, x<0 is meaningless.
This means that if x<5 then the number of diagonals is less than the number of sides, equal for x=5, and more for x>5. ■
Yes. Any polygon with four or more sides has diagonals. However, a triangle does not.
There is no such polygon because a polygon must have at least 3 sides or more.
Any polygon with more than 4 sides.
Interior angles and if it has more than 3 sides also diagonals
No because as the polygon gets smaller the angles and sides get biggerso they can't tessellate by themselves.
Yes. Any polygon with four or more sides has diagonals. However, a triangle does not.
There is no such polygon because a polygon must have at least 3 sides or more.
Any polygon with more than 4 sides.
Interior angles and if it has more than 3 sides also diagonals
No because as the polygon gets smaller the angles and sides get biggerso they can't tessellate by themselves.
I'd have to see one first. So far, no polygon I've ever seen had more sides than angles.
A polygon with 5 or more sides can be a stop sign it has 8 sides.
" A polygon is a closed figure bounded by three or more than three sides." A cube has twelve sides whereas a polygon has more than two sides. Since it is not mentioned which polygon we are talking about we can't tell if cube has more sides.
an octagon is a polygon. an octagon has 8 sides. a polygon is a shape with closed sides.
Any polygon has the same number of angles as its sides.
No, there is no polygon with 7 or more sides can tessellate.
A polygon must have 3 or more sides as with a triangle for example