The first thing to do is to re-write the equation so it is comprehensible.
Then draw a table of 2 horizontal rows across the width of the notepad, label one line 'x' and the other one 'y' , and then draw 11 boxes for x -5 to x +5.
It should look like this:-
x -5 -4 -3 -2 -1 0 +1 +2 +3 +4 + 5
y
(I cannot draw the intervening vertical lines so you will have to imagine them.)
Calculate the figures for 'y' and draw up 'x' and 'y' axes scaled to fit.
If 3X - 4 ------ = 0 1-2X-4 So 3X - 4 ----- = 0 [ x (2X-3) ] 2X-3 3X-4 = 2X-3 [ -2X ] X - 4 = -3 [ +4 ] X= 1
2x
3x + 2x = 5x. 5x= (-4) X = (-4)/5 x= -0.8
Here is how you solve this problem... 5x*4-3x*5*2x-9= (Combine like-terms) 5x-3x*2x= 2x*2x=(2x)2 (Add the rest of the problem) (2x)2*4*5-9=(2x)2*20-9 (2x)2*11 (2x)2 *11= your answer
2x + 1 = -5 so 2x = -6 so that x = -3 Then 3x - 4 = 3*(-3) -4 = -9 - 4 = -13
If you mean: 2x+4y = 4 then the graph joins the points: (2, 0) and (0, 1)
3x - 2x + 4 = 0 3x - 2x = -4 x = -4
If 3X - 4 ------ = 0 1-2X-4 So 3X - 4 ----- = 0 [ x (2X-3) ] 2X-3 3X-4 = 2X-3 [ -2X ] X - 4 = -3 [ +4 ] X= 1
3x+56 = 2x+4 3x-2x = 4-56 x = -52
3x+4 = 2x-3 3x-2x = -3-4 x = -7
2x
2x
3x - 2 = 2x + 4 3x - 2x = 4 + 2 x = 6
-2x^4+16 +2x^4+9-3x^5=-3x^5+25. There is no "answer" because there is no equation.
-2x+20 = 3x 20 = 3x+2x 20 = 5x 4 = x So x = 4
(3x+1)(2x+4) = 6x2+4+2x+12x = 6x2+14x+4
3x + 4 = 8 + 2xSubtract 4 from each side:3x = 4 + 2xSubtract 2x from each side:x = 4