2x+x+5+3x-6=6x-1
x2/(3x2 - 5x - 2) - [2x/ (3x + 1)][1/(x - 2)] = x2/(3x2 - 6x + x - 2) - 2x/(3x + 1)(x - 2) = x2/[3x(x - 2) + (x - 2)] - 2x/(3x + 1)(x - 2) = x2/(3x + 1)(x - 2) - 2x/(3x + 1)(x - 2) = (x2 - 2x)/(3x + 1)(x - 2) = x(x - 2)/(3x + 1)(x - 2) = x/(3x + 1)
(5x 2 - 8x + 1) + (2x 2 - 4x - 11)
6 + 2x = 5x + 9 , 6 - 9 = 5x - 2x , -3 = 3x , x = -1
Cross-multiplying gives: (x + 3)(3 - 2x) = (3x + 1)(2x - 1) ie -2x2 - 3x + 9 = 6x2 - x - 1 add 2x2 to each side: -3x + 9 = 8x2 - x - 1 add 3x to each side: 9 = 8x2 + 2x - 1 subtract 9 from each side: 8x2 + 2x - 10 = 0 divide by 2: 4x2 + x - 5 = 0 Factors are: (4x + 5)(x - 1) x = -1.25 or 1
3x(2x + 1) over (2x - 1)(2x + 1) Cancel out the 2x + 1 Answer: 3x/2x - 1
3x+1+2x-2 = 64 3x+2x = 64-1+2 5x = 65 x = 13
2x+5=3x+1 -x=-4 x=4
-3x + 1
2x+x+5+3x-6=6x-1
3x + 5x = 2x + 28x = 2x + 26x = 2x = (2/6) = 1/3
1 + 3x - x = x - 4 + 2x 1 + 4 = x + 2x - 3x + x 5 = x
6x2 + 11x + 3 = 6x2 + 9x + 2x + 3 = 3x(2x + 3) + 1(2x + 3) = (2x + 3)(3x + 1)
2x = 3x + 1; -x = 1; x = -1.
2x2 + 3x + 1 = (x + 1)(2x + 1)
2x+5+x-1=3x+4
Both equations are equal and so: 3x+1 = 2x+3 3x-2x = 3-1 x = 2 and by substituting y = 7