The Question is not in a proper form. Is it 4-1+5x or 4-1-5x? Or most likely 4-1= 5x, where x would equal 3/5.
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x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
x*-4=8+(2-5*x) =-4x=8+2-x5 x*-4=8+(2-5*x) =-4x=8+2-x5 x*-4=8+(2-5*x) =-4x=8+2-x5
Oh, dude, there are so many ways you can get to 41! Like, you could do 20 + 21, or maybe 82 - 41, or even 2 * 20. Like, the possibilities are endless, man. Just throw some numbers together and see what sticks!