123
x10 = x5.x5 = (x5)2 [x power five whole squared] Equation is x10 + x5 - 2 Replacing x10 (x5)2+x5 - 2 Substituting x5 by Y Equation becomes Y2 + Y - 2 = 0 Y2 + 2Y - Y - 2 = 0 Y(Y + 2) - 1(Y+2) = 0 (Y-1)(Y+2) = 0 The values of Y are 1 and -2 Y = x5 = 1 Therefore, x = 1 Y = x5 = -2 x = fifth root of -2, which is an imaginary value.
x*-4=8+(2-5*x) =-4x=8+2-x5 x*-4=8+(2-5*x) =-4x=8+2-x5 x*-4=8+(2-5*x) =-4x=8+2-x5
x3/x1/2 = x5/2.
x^5 - x^3 + x^2 - 1 = (x - 1)(x + 1)(x + 1)(x^2 - x + 1)
1 x 41, 41 x 1
41 x 1
41 x 32 = 1312 -------------------------------------- The last digit of 41 × 32 is 1 × 2 = 2, but the last digit of 235 is 5. 2 does not equal 5, thus 41 × 32 does not equal 235.
123
One kilogram is equal to 1000 x 1000 = 1000000 milligrams. Therefore, 41 kilograms is equal to 41 x 1000000 = 41000000 milligrams.
-41 Let X= required number: X + 14 = -27 X= -27 - 14 X= -41
205 = 1 x 205, 5 x 41
1 x 287, 7 x 41 = 287
No. it's not a prime number when x = 40, 41, 81,82 ...
1,565 = x5 1,5651/5 = (x5)1/5 1,5651/5 = x5/5 1,5651/5 = x 4.3541 = x
1 x 82, 2 x 41
1 x 123, 3 x 41