x3/x1/2 = x5/2.
Choose the higher power. The LCM of x3 and x5 is x5
x2(x3 + 1) is the best you can do there.
x5 - 2x4 - 24x3 = 0 x3(x2 - 2x - 24) = 0 x3(x2 + 4x - 6x - 24) = 0 x3(x - 6)(x + 4) = 0 x = {-4, 0, 6}
Need to factor under radical cubic root[X5} cubic root[X2 * X3] now bring out the X3 X*cubic root[X2] -----------------------
The X5 has larger headlights than the X3.
x3/x1/2 = x5/2.
Since x3 is a factor of x5, it is automatically the GCF.
x5 = x3 times x2. In this case x3 = 64 so x = cube root of 64 ie 4
No, X5 and it's smaller sibling the X3 is made by Daimler Benz's German competitor BMW. The X5 is based on the 5 series and, not surprisingly, the X3 is based on the smaller 3 series.
Spartanburg, South Carolina.Only X3, X5, X6, and Z4 models are built there.
Choose the higher power. The LCM of x3 and x5 is x5
Choose the lowest of the exponents. The GCF of x3 and x5 is x3
x5 square units.
If x2 and x3 are meant to represent x2 and x3, then x2 times x3 = x5 You find the product of exponent variables by adding the exponents.
x2(x3 + 1) is the best you can do there.
x2 - x10 + x5 - x12 - x3