The first number we call x
The second number is one more than it, so we call it x + 1
The third number is two more than the first, so we call it x + 2
The fourth number is three more than the first, so we call it x + 3
next we sum (add) all the numbers and set it equal to 94
94 = (x) + (x + 1) + (x + 2) + (x + 3)
94 = 4x + 6
88 = 4x
x = 22
So the first number is 22
The Four numbers are 22, 23, 24, and 25.
You can always check your answer by adding them to ensure it works
22 + 23 + 24 + 25 = 94 It works
The factors of 94 are: 1 2 47 94
Negative 94?
The square root of 94 is an irrational number
of means multiply .94 of 10= .94*10=9.4
94 The question cannot be answered because it does not specify what mCBD and x are. The answer is 94.
The smallest of seven consecutive even integers whose sum is 700 is 94.
22 + 23 + 24 + 25 = 94
22+23+24+25 = 94
The numbers are 22, 23, 24 and 25.
They are: 92+93+94+95 = 374
Since consecutive integers differ by one, let's represent them as x, x + 1, x + 2, and x + 3. So we have, x + (x + 1) + (x + 2) + (x + 3) = 94 4x + 6 = 94 4x = 88 x = 22 Thus, the numbers are 22, 23, 24, and 25. (Check:)
x + x + 1 + x + 2 = 279 3x + 3 = 279 3x = 279 - 3 = 276 x = 92 Hence the three consecutive numbers are 92, 93, and 94
There is no such combination.
22, 23, 24 and 25.
How about: 47+47 = 94
90, 94, 96
They are: 92+93+94+95 = 374