if f(x) = x3 + 4x2 - 11x - 30, then yes, (x - 3) is indeed a factor. f(x) = x3 + 4x2 - 11x - 30 ∴ f(x) = (x - 3)(x2 + 7x + 10) ∴ f(x) = (x - 3)(x + 2)(x + 5)
Divide all terms by 4:- x2+7x+12 = (x+3)(x+4) when factored
4x2 + 14x + 12 = 2(2x2 + 7x + 6) = 2(2x + 3)(x + 2)
[ x3 - 4x2 + 7x ] / (x) = x2 - 4x + 7
If you mean x = 3 then the value of 7x-2x is 21-6 = 15
It is: 4x2-7x-15 when factored is (4x+5)(x-3)
4x2-7x-15 = (4x+5)(x-3) when factored
(4x + 5)(x - 3)
4x2-7x-15 (4x+5)(x-3)
(4x+5)(x-3)
(4x - 5)(x + 3) so x = 1.25 or -3
-5
(4x + 5)(x - 3)
x(7x ^2 - 4x + 8)
zero
-3
7x+20-15=7x+5