4500233.00
At the end of the first year, the balance in the account is: 5000(1+.0638). At the end of the second year, the balance in the account is: 5000(1+.0638)(1+.0638). At the end of the third year, the balance in the account is: 5000(1+.0638)(1+.0638)(1+.0638). At the end of the t year, the balance in the account is: 5000(1+.0638)^t. So, at the end of the tenth year, the balance in the account is 5000(1+.0638)^10 = 9,280.47. $5,000 is your principal, and the remaining ($9,280.47 - $5,000) = $4,280.47 is the interest.
You should have 5976.51 provided the fractional units of interest earned are also rolled into the capital.
A+ 5000
It is: 5000-1 = 4999
5000 word at 50 word per minute will take 5000/50 = 100 minutes or 1 hour 40 minutes.
7,093 * * * * * No, that is for 6 years. For 5 years it is 5000*(1.06)5 = 6691.13
Invest at an amount of 200000 at a bank that offers an interest rate of 7,6%p.a Compounded annually for a period of 3 years
5000 x (1.06)5 = 5000 x 1.338 = 6691.13
You will have 5000 dollars × (1 + 8/100)18 = 19,980 dollars.
Using excel FV function all added monies & interest paid @ end of period 5000 invested @ 8% /year for 30 yr no additional monies 50,313.28 with 5000 added end of each year 662,042.62 with 5000/12 added end of each month 679,801.64 with 5000/24 added twice a month 680,679.68
5000 x (1.03)10 = $6719.58
At the end of the first year, the balance in the account is: 5000(1+.0638). At the end of the second year, the balance in the account is: 5000(1+.0638)(1+.0638). At the end of the third year, the balance in the account is: 5000(1+.0638)(1+.0638)(1+.0638). At the end of the t year, the balance in the account is: 5000(1+.0638)^t. So, at the end of the tenth year, the balance in the account is 5000(1+.0638)^10 = 9,280.47. $5,000 is your principal, and the remaining ($9,280.47 - $5,000) = $4,280.47 is the interest.
1200
Principal amount 5,000 Interest rate 9 percent per year = 0.09 Continuous compounding Number of years 7 Future value = P e^rt Future value = (5000) e^(0.09)(7) Amount after 7 years = $9,388.05
To calculate the total amount Wallace will pay on a $5,000 loan with a 4% annual interest rate compounded annually over six years, we use the formula for compound interest: ( A = P(1 + r)^n ), where ( A ) is the total amount, ( P ) is the principal amount ($5,000), ( r ) is the annual interest rate (0.04), and ( n ) is the number of years (6). Plugging in the values: [ A = 5000(1 + 0.04)^6 = 5000(1.265319) \approx 6326.59 ] Therefore, Wallace will pay approximately $6,326.59 in total.
Compounded annually, that's 6125.22
$62130