7,093
* * * * *
No, that is for 6 years. For 5 years it is 5000*(1.06)5 = 6691.13
1200
To calculate the future value of an investment compounded annually, you can use the formula ( A = P(1 + r)^n ), where ( A ) is the amount of money accumulated after n years, ( P ) is the principal amount (initial investment), ( r ) is the annual interest rate, and ( n ) is the number of years. In this case, with ( P = 5000 ), ( r = 0.08 ), and ( n = 10 ), the future value would be ( A = 5000(1 + 0.08)^{10} ). This results in approximately ( A \approx 5000 \times 2.21964 ), which is about $11,098.20. Thus, the investment will grow to around $11,098.20 after 10 years.
It is 5000*(1.06)4*11/2 = 5000*1.0622 = 5000*3.064 approx = 18017.69 You realise, of course, that 6 percent quarterly is equivalent to over 26% per year!
Your going to fail the test.
To calculate the future value of an investment compounded semiannually, you can use the formula: [ A = P \left(1 + \frac{r}{n}\right)^{nt} ] where: ( A ) is the amount of money accumulated after n years, including interest. ( P ) is the principal amount (5000). ( r ) is the annual interest rate (0.06). ( n ) is the number of times that interest is compounded per year (2 for semiannual). ( t ) is the number of years the money is invested (10). Plugging in the values: [ A = 5000 \left(1 + \frac{0.06}{2}\right)^{2 \times 10} = 5000 \left(1 + 0.03\right)^{20} = 5000 \left(1.03\right)^{20} \approx 5000 \times 1.8061 \approx 9030.50 ] Thus, $5000 would grow to approximately $9030.50 in ten years at 6 percent compounded semiannually.
Invest at an amount of 200000 at a bank that offers an interest rate of 7,6%p.a Compounded annually for a period of 3 years
5000 x (1.06)5 = 5000 x 1.338 = 6691.13
4500233.00
You will have 5000 dollars × (1 + 8/100)18 = 19,980 dollars.
5000 x (1.03)10 = $6719.58
1200
To calculate the future value of an investment compounded annually, you can use the formula ( A = P(1 + r)^n ), where ( A ) is the amount of money accumulated after n years, ( P ) is the principal amount (initial investment), ( r ) is the annual interest rate, and ( n ) is the number of years. In this case, with ( P = 5000 ), ( r = 0.08 ), and ( n = 10 ), the future value would be ( A = 5000(1 + 0.08)^{10} ). This results in approximately ( A \approx 5000 \times 2.21964 ), which is about $11,098.20. Thus, the investment will grow to around $11,098.20 after 10 years.
It is 5000*(1.06)4*11/2 = 5000*1.0622 = 5000*3.064 approx = 18017.69 You realise, of course, that 6 percent quarterly is equivalent to over 26% per year!
To calculate the total amount Wallace will pay on a $5,000 loan with a 4% annual interest rate compounded annually over six years, we use the formula for compound interest: ( A = P(1 + r)^n ), where ( A ) is the total amount, ( P ) is the principal amount ($5,000), ( r ) is the annual interest rate (0.04), and ( n ) is the number of years (6). Plugging in the values: [ A = 5000(1 + 0.04)^6 = 5000(1.265319) \approx 6326.59 ] Therefore, Wallace will pay approximately $6,326.59 in total.
Your going to fail the test.
To calculate the future value of an investment compounded semiannually, you can use the formula: [ A = P \left(1 + \frac{r}{n}\right)^{nt} ] where: ( A ) is the amount of money accumulated after n years, including interest. ( P ) is the principal amount (5000). ( r ) is the annual interest rate (0.06). ( n ) is the number of times that interest is compounded per year (2 for semiannual). ( t ) is the number of years the money is invested (10). Plugging in the values: [ A = 5000 \left(1 + \frac{0.06}{2}\right)^{2 \times 10} = 5000 \left(1 + 0.03\right)^{20} = 5000 \left(1.03\right)^{20} \approx 5000 \times 1.8061 \approx 9030.50 ] Thus, $5000 would grow to approximately $9030.50 in ten years at 6 percent compounded semiannually.
If you opened a savings account and deposited 5000 in a six percent interest rate compounded daily, then the amount in the account after 180 days will be 5148.