7.45355992 ==
square root(80) = 8.94427191 80 squared = 6400 not sure what one you want.
square root of 80 simplified= 16*5= 4 squared *5
the 4th root of 80 equals 2.9907
No, 80 is a not perfect square.
If: y = 2x+k then y^2 = 4x^2 +4kx +k^2 If: x^2 +y^2 = 4 then 5x^2 +4kx +(k^2 -4) = 0 Using the discriminant: (4k)^2 -4*5*(k^2 -4) = 0 Removing brackets: 16k^2 -20k^2 +80 = 0 Collecting like terms and subtracting 80 from both sides: -4k^2 = -80 Dividing both sides by -4: k^2 = 20 Square root both sides: k = - square root of 20 and k = + square root of 20 Therefore possible values of k are - square root of 20 and + square root of 20
16
0.64
16
Square root of 81
0.05
square root of 125/80 = 1.25 or 5/4
√80 = 8.94427191
No, the square root of 6400 is 80, and 3200 squared is 10240000.
The positive square root of 80 is approximately 8.94. Since 8.94 is closest to 9, the number closest to the positive square root of 80 is 9.
√6400 = 80* * * * *OR -80
Thr square root of 80656 is 284
square root(80) = 8.94427191 80 squared = 6400 not sure what one you want.