square root(80) = 8.94427191 80 squared = 6400 not sure what one you want.
square root of 80 simplified= 16*5= 4 squared *5
the 4th root of 80 equals 2.9907
No, 80 is a not perfect square.
If: y = 2x+k then y^2 = 4x^2 +4kx +k^2 If: x^2 +y^2 = 4 then 5x^2 +4kx +(k^2 -4) = 0 Using the discriminant: (4k)^2 -4*5*(k^2 -4) = 0 Removing brackets: 16k^2 -20k^2 +80 = 0 Collecting like terms and subtracting 80 from both sides: -4k^2 = -80 Dividing both sides by -4: k^2 = 20 Square root both sides: k = - square root of 20 and k = + square root of 20 Therefore possible values of k are - square root of 20 and + square root of 20
16
0.64
16
Square root of 81
0.05
square root of 125/80 = 1.25 or 5/4
√80 = 8.94427191
No, the square root of 6400 is 80, and 3200 squared is 10240000.
√6400 = 80* * * * *OR -80
Thr square root of 80656 is 284
square root(80) = 8.94427191 80 squared = 6400 not sure what one you want.
4 times the square root of 5