If: y = 2x+k then y^2 = 4x^2 +4kx +k^2
If: x^2 +y^2 = 4 then 5x^2 +4kx +(k^2 -4) = 0
Using the discriminant: (4k)^2 -4*5*(k^2 -4) = 0
Removing brackets: 16k^2 -20k^2 +80 = 0
Collecting like terms and subtracting 80 from both sides: -4k^2 = -80
Dividing both sides by -4: k^2 = 20
Square root both sides: k = - square root of 20 and k = + square root of 20
Therefore possible values of k are - square root of 20 and + square root of 20
Using the discriminant the possible values of k are -9 or 9
-0.82 , -4.82
If: y = kx -2 and y = x^2 -8x+7 Then the values of k work out as -2 and -14 Note that the line makes contact with the curve in a positive direction or a negative direction depending on what value is used for k.
Find the possible values of r in the inequality 5 > r - 3.Answer: r < 8
eating
4,3,2,1,0
product
Using the discriminant the possible values of k are -9 or 9
Since there are no lists following, the answer must be "none of them!"
x (x+5) = 6 X equals 1.
1.25
If: y = kx -2 is a tangent to the curve (which is not a circle) of y = x^2 -8x +7 Then: kx -2 = x^2 -8x +7 Transposing and collecting like terms: (8x+kx) -x^2 -9 = 0 Using the discriminant: (8+k)^2 -4*-1*-9 = 0 Multiplying out the brackets and collecting like terms: 16k +k^2 +28 = 0 Factorizing the above: (k+2)(k+14) = 0 meaning k = -2 or k = -14 Therefore the possible values of k are -2 or -14
It is not possible to give an answer to this question since none of the values are given.
-0.82 , -4.82
The domain is the set of all possible x values, for this problem it would be negative infinity to positive infinity. The range is the set of all possible y values, for this problem it would be -2 too +2
(N-1)=(4-1)= N=3 l=0,1,2,3
Try -1. x=1, x=-6