8x+2=6x+10 8x-6x=10-2 2x=8 x=4 Therefore, x=4.
If 6x + 10 = 11x , then x=2.
8x + 2 = 6x + 10 Subtract 6x from both sides: 2x + 2 = 10 Subtract 2 from both sides: 2x = 8 Divide by 2: x = 4 x = 4
x^2-4x/x^2-6x+8 = x(x-4)/(x-2)(x-4) = x/(x-2)
x2 + 6x + 8 =(x + 2)(x +4)
Dividend: 6x^3 +29^2 -40x -42 Divisor: 6x +5 Quotient: x^2 +4x -10 Remainder: 8
Dividend: 6x^3+29x^2-40x-42 Divisor: 6x+5 Quotient: x^2+4x-10 Remainder: 8
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8x+2=6x+10 8x-6x=10-2 2x=8 x=4 Therefore, x=4.
If you mean 'simplify': (3x + 5)/15 I simply divided the coefficients (numbers) by 2.
8x+2 = 6x-10 8x-6x = -2-10 2x = -12 x = -12/2 X= -6
10+12x=-14 -14-10=12x 12x=-24 x=-2
If 6x + 10 = 11x , then x=2.
x² + 4x -10 + 8/(6x+5)in other words 6x+5 doesn't quite divide completely into the original polynomial; it leaves a remainder of 8.Another Answer:-Dividend: 6x^3 +29x^2 -40x -42Divisor: 6x +5Quotient: x^2 +4x -10Remainder: 8
8x + 2 = 6x + 10 Subtract 6x from both sides: 2x + 2 = 10 Subtract 2 from both sides: 2x = 8 Divide by 2: x = 4 x = 4
12 + x = 6x + 2; subtract 2 from both sides 10 + x. = 6x;; subtract x from both sides 10 = 5x; divide both sides by 5 2 = x; x = 2
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