1335
Let the first number equal x and the second number equal y. You have: A) x + y = 89. B) 4x + y = 155. First you rearrange equation A to obtain equation C) y = 89 - x Then substitute C) into B) to obtain equation D) 4x + 89 - x = 155 Solve equation D) for x to obtain x = 22. Place the value of x in equation C) to obtain y = 67. Thus your answer is {x = 22, y = 67}.
352.83 = (3 x 100) + (5 x 10) + (2 x 1) + (8/10) + (3/100)
89 = 8 x 8 x 8 x 8 x 8 x 8 x 8 x 8 x 8 = 134,217,728.
x + (x+1) + (x + 2) = 267 3x + 3 = 267 3x = 264 x = 88 Answer: 88, 89, 90
89+x=x 89=x-x 89=0 Therefore, "No solution".
x + 89
If x is one of the numbers then the other is (89-x). Both these are positive, so x>0 and 89-x>0 or x<89. Then P(x) = x*(89-x) = 89x-x2 where 0<x<89
279 X 89 = 24,831
1 x 89, 89 x 1
1 x 89, 89 x 1
89 + x = x +89
A pentagon.
Well lots of things, but if u are looking for whole numbers 89 is a prime number, and can only be 1 times 89....
2x + 89 = 78 Therefore, 2x = 78 - 89 x = -11/2 x = -5.5
The awnser to this question, 89 x 18, is 1602!Cait1bh =)
-89 x 1