112
Angle of elevation: tan-1(100/130) = 37.6 degrees rounded to one decimal place
By drawing a sketch from the given information then using triangulation and trigonometry the height of the mountain works out as 3704.435 meters rounded to three decimal places.
tan(A) = 120/100 =39.81 degrees
25 feet
51.34019175 degrees or as 51o20'24.69''
below 90 degrees
The question is not quite clear but if the angle of elevation is 26 degrees at a distance of 165 feet away from the building then its height is 80.47587711 feet. 165*tan(26) = 80.47587711 feet
6
tan40=x/100 100tan(40)=83.9m
18.6 m/52.6 degrees tan= 14.2
The angle of elevation of the ladder leaning against the wall is approximately 48.59 degrees.
the elevation of sea level is 0 degrees.
(Height of the building)/(length of the shadow) = tangent of 31° .Height = 73 tan(31°) = 43.9 feet (rounded)
The typical range of shoulder extension in a healthy adult is between 50 to 60 degrees.
Angle of elevation = 300/50 = 6 tan-1(6) = 80.53767779 degrees or 800 32' 15.64''
As elevation increases temperature decreases reaching the coldest altitude (around -90 degrees C). Once you ascend into the Thermosphere (56 miles high) The temperatures will be extremely high, ranging from 200 degrees C up to 500 Degrees C as you climb in elevation.
The earth is tilted 23 degrees in the orbit plane. This results of lower elevation in the winter and greater elevation in the summer.