(Height of the building)/(length of the shadow) = tangent of 31° .
Height = 73 tan(31°) = 43.9 feet (rounded)
Use the tangent ratio: tan = 93/26 = 74.38 degrees to 2 d.p.
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
You need more info, probably an angle of elevation or something like that. It may be 14ft tall.
Let x = the height of the building. So we have, x/2.6 = 42.25/1.51 x = (2.6)(42.25)/1.51 x =72.75 Thus, the building is 72.75 meter tall.
You take 280 times 10 and then divide that by 14 which equals 200 ft.
It is: 27.35 degrees rounded to two decimal places
If you mean the height of the building then it works out as 466.5063509 feet
tan(A) = 120/100 =39.81 degrees
tan40=x/100 100tan(40)=83.9m
It is nearly 40 feet
It is tan-1(170/200) = 40.365 degrees to 3 decimal places
Use the tangent ratio: tan = 93/26 = 74.38 degrees to 2 d.p.
208 ft pole
If the angle of elevation is 60 degrees then by using the tangent ratio the length of the shadow is 8.66 feet rounded to two decimal places.
To cast a 19 foot shadow the building would have to be 26.91 feet tall. Each foot of building/tree casts 8.47 inches of shadow.
That depends on the angle of elevation which has not been given.
It can be just about any height. To get a specific answer, you would also have to know how high the Sun is in the sky - how many degrees above the horizon; and that can be anythiing between 0 and 90 degrees.