2
It is (-1, 3).
We will be able to identify the answer if we have the equation. We can only check on the coordinates from the given vertex.
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c). For y = 2x² + 4x - 10: → axis of symmetry is x = -4/(2×2) = -4/4 = -1 → vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
Because the base of a cone is round, it is the only three dimensional figure with only one vertex.
It is a turning point. It lies on the axis of symmetry.
It is (-1, 3).
true
Because they represent a pair of coordinates
i think that the range and the domain of a parabola is the coordinates of the vertex
Only equilateral triangles and some irregular polygons of (3n) sides have 3 lines of symmetry. A regular polygon with n sides (or vertices) has n lines of symmetry. If n is even, there are n/2 lines of symmetry from vertex to opposite vertex and another n/2 from the middle of a side to the middle of the opposite side. If n is odd, there are n lines of symmetry from vertex to the midpoint of the opposite side.
False
True. A triangle is said to be inscribed in another figure if each vertex of the triangle lies on the boundary of that figure. For example, a triangle inscribed in a circle has all its vertices touching the circumference of the circle.
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
It depends on what the coordinates of the first three vertices are!
The vertex is at the origin of coordinates ... the point (0, 0).
In a regular pentagon, the lines of symmetry are drawn from each vertex to the midpoint of the edge directly opposite the vertex, so there are five in all.
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES