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What are the vertex and the axis of symmetry of the equation y equals 2x² plus 4x - 10?
Wiki User
∙ 7y ago
In the form y = ax² + bx + c the axis of symmetry is given by the line x = -b/2a
The axis of symmetry runs through the vertex, and the vertex is given by (-b/2a, -b²/4a + c).
For y = 2x² + 4x - 10:
→ axis of symmetry is x = -4/(2×2) = -4/4 = -1
→ vertex = (-1, -4²/(4×2) - 10) = (-1, -16/8 - 10) = (-1, -12)
Wiki User
∙ 7y ago
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Find the vertex and equation of the directri for y2 equals -32x?
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
Fill in the blank The of the vertex of a quadratic equation is determined by substituting the value of x from the axis of symmetry into the quadratic equation?
D
Which equation represents the axis of symmetry of the graph of the equation y equals x2-6x 5?
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
Find the equation of the axis symmetry and the coordinates of the vertex of the graph of each function for y equals 2x plus 4?
I'm assuming that you meant y = 2(x^2) +4. If it were only y = 2x +4, then this would be a linear equation and not a parabola. Anyways, use the equation x = -b/2a to find the x-value of your vertex AND your axis of symmetry. (Given the standard equation y = a(x^2) + bx + c) So, x = -0/2(2) - x = 0 (Axis of Symmetry) Now plug 0 back into your equation to find your y-value of your vertex. y = 2(0^2)+4 y=0 + 4 y = 4 Therefore Vertex = (0,4)
What is an equation of the axis of symmetry of the parabola represented by y equals -x2 plus 6x-4?
Line of symmetry: x = 3
Find the vertex and equation of the directri for y2 equals -32x?
y2 = 32x y = ±√32x the vertex is (0, 0) and the axis of symmetry is x-axis or y = 0
Do all functions of the form y equals ax2 have the same vertex and axis of symmetry?
axis of symmetry is x=0 Vertex is (0,0) So the answer is : YES
What is the equation of the axis of symmetry and the vertex of the graph gx-2x-12x 6?
There is no equation (nor inequality) in the question so there can be no graph - with or without an axis of symmetry.
An equation of a parabola that has x equals 2 as its axis of symmetry is?
How about y = (x - 2)2 = x2 - 4x + 4 ? That is the equation of a parabola whose axis of symmetry is the vertical line, x = 2. Its vertex is located at the point (2, 0).
What is the vertex and the line of symmetry for fx equals 5xsquared?
Vertex = (0,0) Line of symmetry = y axis You should of known that as this function is only X^2
Fill in the blank The of the vertex of a quadratic equation is determined by substituting the value of x from the axis of symmetry into the quadratic equation?
D
What is the equation of the axis of symmetry y equals x2 - 8x plus 16?
y = (x-4)(x-4) * * * The factors above are shown correctly. The axis of symmetry is the vertical line passing through the vertex, which is the point located at (4, 0). The equation of that line is x = 4, which is the answer you requested.
Which equation represents the axis of symmetry of the graph of the equation y equals x2-6x 5?
Assume the expression is: y = x² - 6x + 5 Complete the squares to get: y = x² - 6x + 9 + 5 - 9 = (x - 3)² - 4 By the vertex form: y = a(x - h)² + k where x = h is the axis of symmetry x = 3 is the axis of symmetry.
Tell whether the graph opens up or down Find the coordinates of the vertex Write an equation of the axis of symmetry for the equation y equals 2x2 plus 3x plus 6?
y = 2x2 + 3x + 6 Since a > 0 (a = 2, b = 3, c = 6) the graph opens upward. The coordinates of the vertex are (-b/2a, f(-b/2a)) = (- 0.75, 4.875). The equation of the axis of symmetry is x = -0.75.
Find the equation of the axis symmetry and the coordinates of the vertex of the graph of each function for y equals 2x plus 4?
I'm assuming that you meant y = 2(x^2) +4. If it were only y = 2x +4, then this would be a linear equation and not a parabola. Anyways, use the equation x = -b/2a to find the x-value of your vertex AND your axis of symmetry. (Given the standard equation y = a(x^2) + bx + c) So, x = -0/2(2) - x = 0 (Axis of Symmetry) Now plug 0 back into your equation to find your y-value of your vertex. y = 2(0^2)+4 y=0 + 4 y = 4 Therefore Vertex = (0,4)
What is the axis of symmetry for the parabola with vertex (-2 -4) and directrix y 1?
The axis of symmetry is x = -2.
What is an equation of the axis of symmetry of the parabola represented by y equals -x2 plus 6x-4?
Line of symmetry: x = 3
