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First, let's find the equation of this line in the slope-intercept form, y = mx + b, in order to be able to graph this line.

By using the point-slope form we have:

(y - y1) = m(x - x1) using the point (3, 6) and slope, m = -5;

(y - 6) = -5(x - 3)

y - 6 = -5x + 15 add 6 to both sides;

y = -5x + 21

21 is the y- intercept, so we obtain another point, (0, 21)

By graphing the line with equation y = -5x + 21 we can find the zero of this function, which is the x-intercept. In our case x-intercept is 4.2 (you can use your calculator to find this x- intercept). Or you can make y equal to 0, and solve the equation 0 = -5x + 21 for x.

0 = -5x + 21 subtract 21 to both sides;

-21 = -5x divide by -5 to both sides;

4.2 = x

Now you can see that a right triangle is formed on the first quadrant, with length sides 21 and 4.2. Now you are able to find the area of this right triangle.

A = (1/2)(21)(4.2) = 44.1

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