It depends on where he started from. If he started 13 km from the North Pole, he will end up at the North Pole: so 13 km to the North of his starting point. If he started near the South Pole where the latitude is 6 km, he will again end up 13 km North of his starting point.
If the earth were a flat plane, then he would be approx 14.32 km from his starting point. He would be 27.775 deg East of North.
The ant is at (-0.2794, 0.9602)
Before breakfast , Grandma WRITES in her journal and WALKS a mile.
The X coordinate always goes first think a baby crawls before it walks
Please excuse the horrible ascii graphics (I know the angle is nothing like 15°), but this is easier with a diagram:................./|................/ |............../.. |1500 ft /.... |........../...... |......../........ | E....../.......... |..../............ |../.............. |/15°.......... |----------------E = change in elevationsin = opposite / hypotenusesin(15°) = E / 1500so, E = 1500 * sin(15°) = approx 388.23To the nearest foot, change of elevation = 388 feet
Oh, dude, let me break it down for you. So, if the dog is tethered with a 20-foot lead and the path it walks is 45 feet, that's like a radian situation. The angle in radians would be like 45 feet divided by the radius of the circle, which is 20 feet, so it's around 2.25 radians. But hey, who's counting, right?
The total displacement of the dog from the starting point can be calculated by finding the net displacement, which is the difference between the distances moved in each direction. In this case, the net displacement would be 6m north - 4m south, resulting in a total displacement of 2m north.
Kyoto will be 4 blocks west with reference to his/her starting point
He started from the North Pole.
If she started from the south pole, then she'll wind up 4 miles from her starting point after this series of maneuvers. If she started on or near the equator, then the final distance is roughly 6.4 miles.
Movement in north = 8.4 - 4.7 = 3.7 km Movement in west = 1.2 km Total movement = sqrt(3.7 * 3.7 + 1.2 * 1.2) = 3.89km (approx) Direction North-West asin(1.2/3.7) = 18.92 deg (approx) (from west @ 0 deg to north @ 90 deg)
Not always. They must start at the same point and their displacements must be equal and opposite in order for them to return to the same starting point together.ExampleStarting at the same place, hiker A walks 1km north and hiker B walks 1km south. Hiker A then walks 1km west and hiker B walks 1km east. Hiker A then walks 1km south and hiker B walks 1km north. Finally, hiker A walks 1km east and hiker B walks 1km west, and they both end up together where they started.
Only on Tuesday afternoons.
The sine of an angle is the ratio of the length of the ____________ to the hypotenuse.
white - it is a polar bear!
Girish starts by walking 8 km east, then turns right and walks 3 km south. After that, he turns right again and walks 12 km west. To find his distance from the starting point, we can calculate his final position: he is 8 km east - 12 km west = 4 km west and 3 km south, resulting in a distance of 5 km from the starting point using the Pythagorean theorem (√(4² + 3²) = 5).
The bear is white because it starts at the North Pole, walking south for 1km, then west for 1km (which brings it back to the North Pole, as all lines of longitude converge at the poles), and finally north for 1km, ending up at the point from which it started.
The question does not specify the starting point.