C Square
a square minus b square
sqrt(a)+sqrt(b) is different from sqrt(a+b) unless a=0 and/or b=0. *sqrt=square root of
(a+b+c)²=a²+b²+c²+ 2ab+2bc+2ac
Since a squared plus b squared equals c squared, that is the same as c equals the square root of a squared plus b squared. This can be taken into squaring and square roots to infinity and still equal c, as long as there is the same number of squaring and square roots in the problem. Since this question asks for a and b squared three times, and also three square roots of a and b both, they equal c. Basically, they cancel each other out.
it's the bit in the square root sqrt of (b squared minus 4ac) when a,b and c are the values belonging to the equation ax(sqared) plus bx plus c
a square plus 2ab plus b square
(A+B)2 = (A+B).(A+B) =A2+AB+BA+B2 =A2+2AB+ B2 So the Answer is A + B the whole square is equal to A square plus 2AB plus B square. Avinash.
It is a^2 + b^2, or a*a + b*b.
a square minus b square
6a square plus b square
(a+b)cube = a cube + b cube + 3a square b + 3ab square
sqrt(a)+sqrt(b) is different from sqrt(a+b) unless a=0 and/or b=0. *sqrt=square root of
(a + b)^2
(a+b+c)²=a²+b²+c²+ 2ab+2bc+2ac
The whole square of the sum of two terms, ( (a + b)^2 ), can be expanded using the formula: ( (a + b)^2 = a^2 + 2ab + b^2 ). This expression represents the square of ( a ) plus twice the product of ( a ) and ( b ), plus the square of ( b ). It highlights the relationship between the individual squares of the terms and their product, emphasizing how they combine in the squared result.
It's the square root of a2+b2. It cannot be simplified. It is NOT a+b. The answer is c square.
A^2 + b = 7 A + B^2 =11 -------------- A=2 and B=34(2^2) + 3 = 7 2 + 9(3^2) = 11