For a regular polygon with sides n, the sum of the interior angles = (n-2)180Therefore, a regular polygon has interior angle sum equal to 540o.(5-2)180=(3)180=540
15
(n-2)(180) use that formula to find the sum of the interior angles of a polygon in degree
The question has been asked "What is the angle sum of a thirteen sided polygon?" The answer to this question is 1980 degrees. The sum of the interior angles of a polygon of n sides = 180(n - 2)
Anything you like. Any single interior angle of a polygon is indeterminate - the only constraint is on the sum of all the interior angles.
540 degree for the interior angles
A pentagon is a polygon with an interior angle sum measure of 540 degrees and 5 sides.
For a regular polygon with sides n, the sum of the interior angles = (n-2)180Therefore, a regular polygon has interior angle sum equal to 540o.(5-2)180=(3)180=540
540 degrees
Exterior angles 360 degrees Interior angles 540 degrees
For interior, the angle sum is 540 degrees, for exterior, the angle sum is 1260 degrees. * * * * * Partially correct! The sum of the exterior angles of any polygon is 360 degrees. The exterior angle is the supplement of the interior angle (180 - interior), NOT the reflex angle (360- interior). So the sum given 1260, which is based on the reflex angles is incorrect.
540 degrees
A pentagon (5 sided polygon) has the sum of its interior angles equal 540°.The formula for a general N-sided polygon is:[sum of interior angles] = N*180° - 360°
There are 5 interior angles and each one measures 108 degrees (180-72). Since the sum of exterior angles of any polygon is 360⁰, then that polygon would have 5 angles (360/72). So the sum of interior angle measures is 540⁰.
No but it can be 540 degrees
the sum of the interior angles of a 3 sided polygon is = 180 degrees. the sum of the interior angles of any polygon is given by 540/n. in this case n is = 3
Each interior angle is 108 degrees and its 5 angles add up to 540 degrees