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x = the width of the path.

A = area of path = (15+x)(11+x) - (15*11) = (15*11)+15x+11x-(15*11) = 15x+11x = 26x

192 ft2 = 26x

x = 192/26 ~= 7.38 feet.

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Q: A rectangular garden has dimensions of 15 feet by 11 feet A gravel path of uniform width is to be built around the garden How wide can the path be if there is enough gravel for 192 square feet?
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