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If a area has of 5000 square yards if its width is 50 yards what is its length?
Its length is 100 square yards.
The perimeter of a rectangle is 200 inches the length exceeds the width by 96 inches?
Length + width = half perimeter = 100". Length is 98", width is 2"
The width of a wall is 22m and its height is 3.5m How many bricks of length 22cm and width is 7 cm can make a single wall?
Width = 22m Height = 3.5m --- Convert both of these into cm to convert into same units Width = 22 x 100 = 2200cm Height = 3.5 x 100 = 350cm Next find the area of the wall ---Area of rectangle = height x width Area of the wall = 2200 x 350 = 770,000 sq. cm Now for the bricks Length = 22cm Width = 7cm Area = 22 x 7 = 154 sq.cm To find the number of bricks needed we have to divide the area of the wall with the area of one brick 770,000 / 154 =5000 Therefore 5000 bricks are needed to make a single wall
What is the width of a rectangle if the perimeter is 100 feet and length is 30 feet?
20 feet
The length of a rectangular poster is 7 in greater than the width the perimeter is 114 find the width and length?
Let the width be x and the length be x+7: 2(x+x+7) = 114 4x+14 = 114 4x = 114-14 4x = 100 x = 25 Therefore: width = 25 units and length = 32 units
What is the length when the width is 11 meters and the surface area is 100 square meters?
Area = length times width A = LW 100 m^2 = L(11 m) = 9.090909091
What is the length of a garden with a width of 12.5 and an area of 100 square meters?
The length is 100 / 12.5 = 8 meters.
How do you break down area to lengths?
If you have the area you must have one other number, like the width of the field. So if the area of the field is 10,000 square feet, and the width is 100 feet, then divide the area by the width and you have the length. Area of a rectangle = length x width
The area of a rectangle is 50 the length of the rectangle is 100 what is the width of the rectangle?
0.5
If a area has of 5000 square yards if its width is 50 yards what is its length?
Its length is 100 square yards.
The length of a rectanfular play field is 12 meters longer than the width the area of the play field is 11200 square meters Formulate and solve an equation to find the length and width of the play fie?
width =100 mts length= 100+12= 112 mts Area= 112*100=11200 m^2
How big is 10000 square meters?
As a square area it is 100 meters in width and 100 meters in length. Is that big?
What is the area of a square with length 10m width 10m and a rectangle with length 14m and width 10?
Area of square: 10*10 = 100 square m Area of rectangle: 14*10 = 140 square m
What is the width of a rectangle with an area of 300 sq ft if its length is 3 feet?
The other length is 100 feet because 3*100 = 300.
What is the area of a long shape?
If the area is of a rectangle, it is simply the length times the width. If you have a rectangle with sides of 2 and 50 then the area is 100.
The width of a rectangle measures 4 cm less than the length What is the area of the rectangle if it's perimeter is equal to 100cm?
Let X represent the length, then X-4 represents the width. Perimeter of the rectangle is length plus width multiplied by two. Hence, 2(X + X - 4) = 100; 4X - 8 = 100; 4X = 108; X = 27. The length is 27 mm and the width is 27 - 4 = 23 mm. width = w length = w + 4 perimeter = w + w + w + 4 + w + 4 = 100 4w + 8 = 100 4w = 92 w = 23 width = 23 length = 27 area = 23 x 27 = 621
What is the length and width of a rectangle that has a perimeter of 20 inches and an area of 24.4524 square inches showing work with final answers?
What do we know about the perimeter of a rectangle? perimeter = 2 × (length + width) → 2 × (length + width) = 20 in → length + width = 10 in → length = 10 in - width What do we know about the area of a rectangle: area = length × width → length × width = 24.4524 in² But from the perimeter we know the length in terms of the width and can substitute it in: → (10 in - width) × width = 24.4524 in² → 10 in × width - width² = 24.4524 in² → width² - 10 in × width + 24.4524 in² = 0 This is a quadratic which can be solved by using the formula: ax² + bx + c → x = (-b ±√(b² - 4ac)) / (2a) → width = (-10 ±√(10² - 4 × 1 × 24.4524)) / (2 × 1) in → width = -5 ± ½√(100 - 97.8096) in → width = -5 ±½√2.1904 in → width = -5 ± 0.74 in → width = 4.26 in or 5.74 in → length = 10 in - 4.26 in = 5.74 in or 10 in - 5.74 in = 4.26 in (respectively) By convention the width is the shorter length (though it doesn't have to be) making the width 4.26 in and the length 5.74 in. Thus the rectangle is 5.74 in by 4.26 in
