317
35 mph
Provided the wind remains constant the jet is travelling at a rate of 791.3 km/h with no wind. The windspeed is 118.7 km/h btw.
It might just be 10%.
The answer is 2.4 km/h. Distance = Speed * Time. For the initial journey: d=4*6 =24 km He took the same path back thus the distance is the same. 24=10*speed Speed = 2.4 km/h
More land (estates, manors) more power, more titles and the king's favor.
something to do with turbulants?
Flight is considered to be when the weight of the aircraft is off the ground. The definition can be more complicated if you want to apply for a record. "Powered Flight" is demonstrated by an airplane that can fly on its own power and is not dropped from a height. To test this, they usually required the airplane to fly a circuitous route or fly out a distance and return. This was to ensure that the aircraft was not being lifted by a strong wind.
275 km/hr
275 km/hr
275 km/hr
If you are not a Canadian citizen, you can not board a flight to Canada without a return ticket. Buy a return, make sure that the return flight date can be changed.
Let the speed of the airplane in still air be represented by V.Velocity = Distance ÷ Time, thus Distance = Velocity x Time.D = 4(V + 20) = 5(V - 20), then 4V + 80 = 5V - 100 : V = 180 kphThe speed in still air is 180kph
105 mph
yes or you will be stranded, omg guys,we cant have that cant we? Obviously! I'm saying it's cheaper to get a return flight instead of one way... Can I book a return and not get on it?
It depends on the type of ticket that you have. The simple solution is not to miss your flight!
A tourist visa is valid for no more then 90 days, and you must have "proof" (an airplane or boat ticket home or to another country) of leaving the country within that time or you will not be allowed to enter.In actuality, you will not be allowed to board the flight to get to Australia without proof of having a ticket to leave.
Danger - 1950 Return Flight 3-33 was released on: USA: 2 June 1953