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An algebra class of 21 students must send 5 students to meet with the principal How many different groups of 5 students could be formed from this class?
Wiki User
∙ 14y ago
To find the number of different groups (a) within a larger group (b), use the formula b!/a!.(b-a)! where the ! sign indicates "factorial". In your problem b = 21 and a = 5 so we have 21!/(5!.16!) this simplifies to 21.20.19.18.17/5.4.3.2 cancelling leaves 21.19.3.17 ie 20349
Wiki User
∙ 14y ago
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How many different committees can be formed from 6 teachers and 33 students if the committee consists of 3 teachers and 2 students?
There are 10560 possible committees.
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The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
How many different three member teams can be formed from six students?
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A school has 18 classes with 35 students in each class. In order to reduce class size to 30, how many new classes must be formed?
How many three member teams can be formed from a group of six students?
2 groups. 2 x 3= 6
How many different three-member teams can be formed from six students?
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How many different 3 member teams can be formed from a group of 6 students?
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How many different committees can be formed from 6 teachers and 33 students if the committee consists of 3 teachers and 2 students?
There are 10560 possible committees.
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20 x 19 x 18/3 x 2 = 1,140 groups
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There are (10 x 9)/2 = 45 different possible pairs of 2 teachers. For each of these . . .There are (30 x 29)/2 = 435 different possible pairs of students.The total number of different committees that can be formed is (45 x 435) = 19,575 .
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This question is impossible to understand. Are you asking how algebra was discovered, what its fundamental principles are, or how it is taught in schools? Please resubmit your question specifying what you are looking for.
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