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How many different arrangements of 7 letters can be formed from the letters in the word ALGEBRA?
The number of 7 letter permutations of the word ALGEBRA is the same as the number of permutation of 7 things taken 7 at a time, which is 5040. However, since the letter A is duplicated once, you have to divide by 2 in order to find out the number of distinct permutations, which is 2520.
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How many different arrangements can be formed using the letters in the word ABSOLUTE if each letter is used only once?
That's eight letters, so: 8! = 40320 different arrangements. n! means "factorial", and the expression expands to n*(n - 1)*(n - 2) ... * 2 * 1
How many different nine letter arrangements can be formed from the nine letters of the word apparatus?
Answer 9!/3!2!=30240 Note there are three a's and two p's and a total of 9 letters in apparatus. So there are 9 choices for the first letter, and 8 for the next, then 7 for the third etc. The we divide by 3! and 2! to avoid overcounting. The answer is 9!/3!2! The numerator can be written as 9! which is pronounced 9 factorial. Then we divide that by 3! times 2! In general if you have have n letters, there are n! words you can make, However, if some of the letters are repeated you must divide to avoid overcounting. If letter a is repeated r1 times, b r2 times, c r3 times.. etc, Then the number of words is n!/r1!r2!r3!
Which two upper case letters are formed with only two perpendicular line segments?
The letters T and L are formed as asked.l and t from fiona1234
An algebra class of 21 students must send 5 students to meet with the principal How many different groups of 5 students could be formed from this class?
To find the number of different groups (a) within a larger group (b), use the formula b!/a!.(b-a)! where the ! sign indicates "factorial". In your problem b = 21 and a = 5 so we have 21!/(5!.16!) this simplifies to 21.20.19.18.17/5.4.3.2 cancelling leaves 21.19.3.17 ie 20349
Which 2 capital letters are formed with only 2 perpendicular line segments?
X and T because the they can still make the T shape and still be perpendicular
How many different arrangements of letters in the word BOUGHT can be formed if the vowels must be kept next to each other?
240
How many different nine letter arrangements can be formed from the nine letters of the word logarithm?
Algorithm is the only nine letter word.
How many different 5 letter arrangements can be formed from the letters in the name CATHY if each letter is used only once in each arrangement?
120
How many different arrangements can be formed using the letters in the word ABSOLUTE if each letter is used only once?
That's eight letters, so: 8! = 40320 different arrangements. n! means "factorial", and the expression expands to n*(n - 1)*(n - 2) ... * 2 * 1
How many different 5 letter arrangements can be formed from the letters in the word Danny?
The number of 5 letter arrangements of the letters in the word DANNY is the same as the number of permutations of 5 things taken 5 at a time, which is 120. However, since the letter N is repeated once, the number of distinct permutations is one half of that, or 60.
How many different 6 letter arrangements can be formed using the letters absent if each letter is used only once?
720 (6 x 5 x 4 x 3 x 2)
How many different 4-letter words can be formed using the letters of the word NATION?
8 different 4-letter words can be formed from the letters of the word "Nation".
How many different 7 letter arrangements can be formed from the letters in the word success?
There are 7!/(3!*2!) = 420 ways.7! for the seven letters in "success", butthere are 3 s which are indistinguishable, so divide by 3!there are 2 c which are indistinguishable, so divide by 2!
How many different words can be formed using letters gazebo?
Words that can be made with the letters in 'gazebo' are:aageagobagbebegboabogegogabgazegogob
How many words can you make from season greetings?
There are a total of 15 letters in "season greetings." To calculate the number of words that can be formed, we first need to determine the number of unique arrangements of these letters. This can be calculated using the formula for permutations of a multiset, which is 15! / (2! * 2! * 2! * 2! * 2! * 2! * 1!). This results in 1,816,214,400 unique arrangements. However, not all of these arrangements will form valid English words, as many will be nonsensical combinations of letters.
How many different 5-letter arrangements can be formed from the letters in the name tyler if each letter is used only once in each arrangement?
The answer is 5!, 5 factorial. This equals 5 X 4 X 3 X 2 X 1, which is 120.
How many different numbers can be formed by various arrangements of the six digits 111123?
6*5*4*3*2*1=720
