y=x2+3
x1=1
x2=2
y(x1) = 1*1+3 = 4
y(x2) = 2*2+3 = 7
x2/x1 = 2, While y2/y1 = 7/4 !=2, and thus the function is nonlinear.
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You must provide a complete equation for the function. Do you mean f(x) = 1.5x + 7.6 or something else?
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The first step not possible in solving an equation algebraically is not to provide an equation in the first place in which it appears to be so in this case.
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Without further information, "y" can have any value.