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To work out the equation of a straight line the slope and an (x, y) coordinate must be given
If the slope is m, then the equation is y - 7 = m*(x + 3)
Point: (7, -5) Slope: -4/7 Equation: 7y = -4x-7
There is a standard equation for a straight line. It is y = mx + b. m is the slope and b is the y-intercept (when x = 0). In the question m = -4 and is therefore the slope of the line represented by the equation y = -4x + 7.
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If the slope is 7 and the coordinate is (8, 5) then the straight line equation is y=7x-51
To work out the equation of a straight line the slope and an (x, y) coordinate must be given
If the slope is m, then the equation is y - 7 = m*(x + 3)
-7 is.
Point: (7, -5) Slope: -4/7 Equation: 7y = -4x-7
The equation (7x) can be interpreted as (y = 7x + 0), which is in the slope-intercept form (y = mx + b) where (m) represents the slope and (b) is the y-intercept. In this case, the slope (m) is 7. Therefore, the slope of the line represented by the equation (7x) is 7.
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y = x - 7 or, y = 1*x - 7 so that the slope is 1.
A line that is parallel to the line represented by the equation ( y = -3x - 7 ) will have the same slope. Since the slope of the given line is -3, any parallel line will also have a slope of -3. Therefore, an equation representing a parallel line can be written in the form ( y = -3x + b ), where ( b ) is any real number.
It is -7
y=4x -7