If the slope is 7 and the coordinate is (8, 5) then the straight line equation is y=7x-51
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
what is the slope of the line containing points (5-,-2) and (-5,3)? 2
Here is how to solve it. First, find the slope of the given line. To do this, solve the equation for "y". That will convert the equation to the slope-intercept form. From there, you can immediately read off the slope. Since parallel lines have the same slope, the line you are looking for will have the same slope. Now you need to use the point-slope form of the equation, with the given point, and the slope you just calculated. Finally, solve this equation for "y" to bring it into the requested slope-intercept form.
Another point is needed to work out the slope and its straight line equation. Slope is worked out as: (y2-y1)/(x2-x1) ----------------------- With slope m and going through a point (x0, y0), a line has equation: y - y0 = m(x - x0) Thus the point-slope equation of a line with slope m through the point (-1, 2) is given by: y - 2 = m(x - -1) → y - 2 = m(x + 1)
if a line has a slope of -2 and a point on the line has coordinates of (3, -5) write an equation for the line in point slope form
Assuming the point is (3, -6) and the slope 1, the equation is x - y - 9 = 0
Which of the following is the point-slope equation of the line with a slope equals -4 and a point of -2 3?
That will depend on the value of the slope which has not been given.
The slope of a curved line at a point is the slope of the tangent to the curve at that point. If you know the equation of the curve and the curve is well behaved, you can find the derivative of the equation of the curve. The value of the derivative, at the point in question, is the slope of the curved line at that point.
You can have infinitely many lines through one specific point, each with a different equation. If you want to have a general equation for ANY line that goes through that point, use the point-slope equation for a line, and use a variable for the slope.
Given a point P = (a,b) and slope m, the equation of a line through P with slope m is (y-b) = m(x-a)
If you mean a slope of -5 and a point of (6, 3) then the equation is y = -5x+33
Write the equation in slope-intercept form of the line that has a slope of 2 and contains the point (1, 1).
It is x + 3 = 0.
If the slope is 2/3 and the coordinate is (2, -1) then the straight line equation is 3y=2x-7
When it is a line through the origin.