Those letters are indeed often used to represent integers. But in practice, it's best to always check what assumptions are made. If certain variables (letters) are meant to be integers only, for example for some theorem, this should be stated explicitly.
No.Suppose a and b are two rational numbers.Then they can be written as follows: a = p/q, b = r/s where p, q, r and s are integers and q, s >0.Then a*b = (p*r)/(q*s).Using the properties of integers, p*r and q*s are integers and q*s is non-zero. So a*b can be expressed as a ratio of two integers and so the product is rational.
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A number is said to be rational if it can be expressed as a ratio of two integers. That is, a number x is rational if and only if it is equivalent to p/q for some integers p and q where q is not 0.
The ratio of two integers P and Q can be expressed as P : Q or P/Q. In both cases, you may divided P and Q by their greatest common factor so as to express the ratio in its simplest form. Alternatively, you may multiply both by some number so that the first part is 1 or the second part is 1 (both unit ratios), or the second part is 100 (a percentage), or a million (part per million) and so on.
Rational.In mathematics, a rational number is any numberthat can be expressed as the quotient or fraction p/q of two integers, a numerator p and a non-zero denominator q.
An irrational number cannot be expressed as a ratio in the form p/q where p and q are integers and q > 0. Integers can be.
The ratio of two integers, p and q where q is not 0, can be expressed as p:q or p/q.
A rational number is a number than can be written p/q with p and q integers Any integers can be written this was with q=1
The vast majority of rational numbers are not integers. They are numbers which can be written in the form p/q where p and q are integers which are co-prime and q > 1.
All integers {..., -2, -1, 0, 1, 2, ...} are rational numbers because they can be expressed as p/q where p and q are integers. Let p equal whatever the integer is and q equal 1. Then p/q = p/1 = p where p is any integer. Thus, all integers are rational numbers.
By definition, every rational number x can be expressed as a ratio p/q where p and q are integers and q is not zero. Consider -p/q. Then by the properties of integers, -p is an integer and is the additive inverse of p. Therefore p + (-p) = 0Then p/q + (-p/q) = [p + (-p)] /q = 0/q.Also, -p/q is a ratio of two integers, with q non-zero and so -p/q is also a rational number. That is, -p/q is the additive inverse of x, expressed as a ratio.
If a is rational then there exist integers p and q such that a = p/q where q>0. Similarly, b = r/s for some integers r and s (s>0) Then a*b = p/q * r/s = (p*r)/(q*s) Now, since p, q r and s are integers, p*r and q*s are integers. Also, q and s > 0 means that q*s > 0 Thus a*b can be expressed as x/y where p and r are integers implies that x = p*r is an integer q and s are positive integers implies that y = q*s is a positive integer. That is, a*b is rational.
The standard form is p/q where p and q are integers and q > 0.
A proper fraction is a ratio in the form p/q where p and q are integers and q>0.
They are numbers that can be expressed as -p/q where p and q are positive integers.
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No.Suppose a and b are two rational numbers.Then they can be written as follows: a = p/q, b = r/s where p, q, r and s are integers and q, s >0.Then a*b = (p*r)/(q*s).Using the properties of integers, p*r and q*s are integers and q*s is non-zero. So a*b can be expressed as a ratio of two integers and so the product is rational.