answersLogoWhite

0


Best Answer

By definition, every rational number x can be expressed as a ratio p/q where p and q are integers and q is not zero. Consider -p/q. Then by the properties of integers, -p is an integer and is the additive inverse of p. Therefore p + (-p) = 0

Then p/q + (-p/q) = [p + (-p)] /q = 0/q.


Also, -p/q is a ratio of two integers, with q non-zero and so -p/q is also a rational number. That is, -p/q is the additive inverse of x, expressed as a ratio.


User Avatar

Wiki User

7y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: How does every rational number have an additive inverse?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Other Math

Does every integer has an additive inverse?

The additive inverse states that a number added to its opposite will equal zero. A + (-A) = 0. The "opposite" number here is the "negative" of the number. For any number n, the additive inverse is (-1)n. So therefore yes.


What is a number added to its additive inverse will always have a sum of zero?

It is a tautological description of one of the basic properties of numbers used in the branch of mathematics called Analysis: Property 2: there exists an additive identity, called 0; for every number n: n + 0 = 0 + n = n. Property 3: there exists an additive inverse, of every number n denoted by (-n) such that n + (-n) = (-n) + n = 0 (the additive identity).


What is the multiplication inverse of 8?

The multiplicative inverse is when you multiply a certain number, and the product is itself, the number. So, the multiplicative inverse of 8 is of course, 1. For every number, the multiplicative number is 1, because a certain number times 1 is equal to the certain number. It's simple!!


Every rational number is a real number?

Yes it is, but not every real number is a rational number


Properties of addition?

If 'a', 'b' and 'c' are any three numbers, then the properties of addition are:* Associative: the value of a + (b + c) is the same as (a + b) + c;* Additive identity: there exists zero (0) such that a + 0 = a;* Additive inverse: for every number a there is an additive inverse, denoted by (-a), such that a + (-a) = (-a) + a = 0;* Commutative: the value of a + b is the same as b + a;* Closed: the value of a + b is another number in the original set of a and b, for example, if aand b are both integers, then a + b will also be an integer.

Related questions

Is a additive inverse of any rational number a negative number?

The additive inverse of EVERY positive rational number is a negative number.


Does every rational number have an additive inverse and why?

yes


Does every rational number have an additive inverse?

Yes.


Why does every rational number have a additive inverse?

The rational numbers form an algebraic structure with respect to addition and this structure is called a group. And it is the property of a group that every element in it has an additive inverse.


Why does every rational number have an additive inverse?

It is a fundamental requirement of algebraic structures called groups.


What is the aditive inverse property?

For every number, a,there exists a number called the additive inverse, -a, such that a + -a = 0.


Does every integer has an additive inverse?

The additive inverse states that a number added to its opposite will equal zero. A + (-A) = 0. The "opposite" number here is the "negative" of the number. For any number n, the additive inverse is (-1)n. So therefore yes.


Does every natural number have an additive inverse?

Yes. Just put a minus sign in front of it. Note that except for the zero, the additive inverse is no longer a natural number.


Does every integer have an additive inverse?

Yes.


When the additive inverse of a number equal to the absolute value of the number?

One example would be a Galois Field size 4 (ie GF(4)). Here, the elements are {0,1,2,3} and every element is its own additive inverse.


What is the additive inverse of the complex number 8 plus 3i?

To form the additive inverse, negate all parts of the complex number → 8 + 3i → -8 - 3i The sum of a number and its additive inverse is 0: (8 + 3i) + (-8 - 3i) = (8 + -8) + (3 + -3)i = (8 - 8) + (3 - 3)i = 0 + 0i = 0.


What is a number added to its additive inverse will always have a sum of zero?

It is a tautological description of one of the basic properties of numbers used in the branch of mathematics called Analysis: Property 2: there exists an additive identity, called 0; for every number n: n + 0 = 0 + n = n. Property 3: there exists an additive inverse, of every number n denoted by (-n) such that n + (-n) = (-n) + n = 0 (the additive identity).