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Subjects>Math>Algebra

Are the lines y -x-4 and 5x 5y 20 perpendicular?

Anonymous

∙ 8y ago

Updated: 4/28/2022

With out any equality signs and not knowing the plus or minus values of some of the given terms they can't be considered to be straight line equations.

Wiki User

∙ 8y ago

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Q: Are the lines y -x-4 and 5x 5y 20 perpendicular?

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Continue Learning about Algebra

Is 2x-5y-3 perpendicular to 5x 2y6?

If the slopes of the lines are negative reciprocals, then the lines are perpendicular.2x - 5y = -3 subtract 2x to both sides-5y = -2x - 3 divide both sides by -5y = (2/5)x +3/55x + 2y = 6 subtract 5x to both sides2y = -5x + 6 divide both sides by 2y = (-5/2)x + 3Yes, the lines are perpendicular.

What is the equation of the line that passes through the point of 3 -4 and is perpendicular to the line 5x -2y equals 3?

Known equation: 5x -2y=3 => y=5/2x -1.5 Slope of equation: 5/2 Perpendicular slope: -2/5 Perpendicular equation: y--4=-2/5(x-3) => 5y--20=-2x+6 => 5y=-2x-14 Therefore the perpendicular in its general form is: 2x+5y+14 = 0

What is an equivalent expression to -5x-5y?

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What are the x and y intercepts of -2x equals 20 plus 5y?

-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4

What is the equation of the line passing through 3 -4 and it is perpendicular to the line 5x -2y equals 3?

Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0

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