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With out any equality signs and not knowing the plus or minus values of some of the given terms they can't be considered to be straight line equations.
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Is 2x-5y-3 perpendicular to 5x 2y6?
If the slopes of the lines are negative reciprocals, then the lines are perpendicular.2x - 5y = -3 subtract 2x to both sides-5y = -2x - 3 divide both sides by -5y = (2/5)x +3/55x + 2y = 6 subtract 5x to both sides2y = -5x + 6 divide both sides by 2y = (-5/2)x + 3Yes, the lines are perpendicular.
What is the equation of the line that passes through the point of 3 -4 and is perpendicular to the line 5x -2y equals 3?
Known equation: 5x -2y=3 => y=5/2x -1.5 Slope of equation: 5/2 Perpendicular slope: -2/5 Perpendicular equation: y--4=-2/5(x-3) => 5y--20=-2x+6 => 5y=-2x-14 Therefore the perpendicular in its general form is: 2x+5y+14 = 0
What is an equivalent expression to -5x-5y?
0
What are the x and y intercepts of -2x equals 20 plus 5y?
-2x = 20 + 5y-2x - 20 = 5y-2/5x - 4 = yX Intercept = (-10,0) or -10Y Intercept = (0,-4) or -4
What is the equation of the line passing through 3 -4 and it is perpendicular to the line 5x -2y equals 3?
Known equation: 5x -2y = 3 or y = 5/2x -3/2 Slope of equation: 5/2 Slope of perpendicular equation: -2/5 Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14 Perpendicular equation in its general form: 2x+5y+14 = 0
Are the lines y equals -x-4 and 5x plus 5y equals 20 perpendicular?
No. No. No. No.
Is 2x-5y-3 perpendicular to 5x 2y6?
If the slopes of the lines are negative reciprocals, then the lines are perpendicular.2x - 5y = -3 subtract 2x to both sides-5y = -2x - 3 divide both sides by -5y = (2/5)x +3/55x + 2y = 6 subtract 5x to both sides2y = -5x + 6 divide both sides by 2y = (-5/2)x + 3Yes, the lines are perpendicular.
What lines would these be 2x plus 5y equals 6 and 5x-2y equals 8?
2X + 5Y = 6 5Y = - 2X + 6 Y = - 2/5X + 6/5 ----------------------------------and 5X - 2Y = 8 2Y = - 5X + 8 Y = - 5/2 + 4 ------------------- Look like intersecting lines, though not perpendicular
What is the equation of a line that passes through 3 -4 and is perpendicular to 5x -2y equals 3 on the Cartesian plane?
Perpendicular slope: -2/5 Perpendicular equation: y--4 = -2/5(x-3) => 5y--20 = -2x-3 => 5y = -2x-14 Perpendicular equation in its general form: 2x+5y+14 = 0
What is the equation of the line that passes through the point of 3 -4 and is perpendicular to the line 5x -2y equals 3?
Known equation: 5x -2y=3 => y=5/2x -1.5 Slope of equation: 5/2 Perpendicular slope: -2/5 Perpendicular equation: y--4=-2/5(x-3) => 5y--20=-2x+6 => 5y=-2x-14 Therefore the perpendicular in its general form is: 2x+5y+14 = 0
Are the lines y equals negative x minus 4 and 5x plus 5y equals 20 perpendicular explain your answer?
y=-x-4as this is in the form of y=mx+b, the slope of this line is -1.5x + 5y = 20x + y = 4y = -x + 4the slope of this line is -1.Since the slope of each of the two lines are the same (-1) they are in fact parallel to each other, not perpendicular.
Is 3x plus 5y equals 12 perpendicular to 5x plus 3y equals 18?
No.
What is an equivalent expression to -5x-5y?
0
Are 5x-7y equals 6 and 5y-7x equals 4 perpendicular?
No, because a slope needs to be negative and opposite the other slope to be perpendicular and in this problem it is not.
What is the equation to a line that is perpendicular to the graph of 5 x minus 3 y equals 9 and the two lines intersect at x equals 15?
It is 3x + 5y = 155 The slope of the line 5x -3y = 9: 5x - 3y = 9 → 3y = 5x - 9 → y = 5/3 x - 3 → slope is 5/3 → slope of perpendicular line is -3/5 Intercept at x = 15 → y = 5/3 x 15 - 3 = 22 → equation of perpendicular line is: y - 22 = -3/5 (x - 15) → 5y - 110 = -3x + 45 → 3x + 5y = 155
How do you solve 4x-5y plus 20 equals 0?
4x-5y+20 = 0 -5y = -4x-20 y = 4/5x+4 which is now in slope intercept form
4x - 5y equals -20 is it a positive or negative slope?
Let's see. 4X - 5Y = - 20 - 5Y = - 4X - 20 Y = 4/5X + 20 slope(m) = 4/5 Is positive
