Known equation: 5x -2y = 3 or y = 5/2x -3/2
Slope of equation: 5/2
Slope of perpendicular equation: -2/5
Perpendicular equation: y --4 = -2/5(x -3) => 5y = -2x -14
Perpendicular equation in its general form: 2x+5y+14 = 0
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y = 1/3x+4/3
The line "x = 6" will be perpendicular to any line "y = C", where C is any constant. That means that the line which is perpendicular to "x=6" and passes through [-4, 5] will be "y = 5"
Perpendicular equation: 4x +3y -5 = 0 Perpendicular slope: -4/3 Slope of line: 3/4 Point of line: (-2, -3) Equation of line: y - -3=3/4(x - -2) => 4y - -12=3x - -6 => 4y = 3x -6 Therefore the equation of the line is: 4y = 3x -6 or 3x -4y -6 = 0
It works out in its general form as: 3x-4y-6 = 0
The question is not quite clear but one equation will be y = 3x+6 and the other equation will have a slope of minus 1/3