yes
The answer is 1
1
Y=1/x
In the case of real roots, you could, but the second part of the ordered pair (the ordinate) will always be zero, so there is not much point.In the case of complex roots (or real roots in the complex field), you could list them as ordered pairs: with (a, b) representing a + bi where i is the imaginary square root of -1..
A direct variation is when the value of K in multiple proportions is all divisible by the same number for example: XY=(1)(10) K=10 XY=(2)(20) K=40 XY=(3)(30) K=90 XY=(4)(40) K=160 In this situation the constant (K) of each proportion is divisible by 10 making the multiple equations a direct variation.
No. For direct variation, any order pair with a 0 in it MUST be (0,0).
-1 is a one-dimensional entity. It can have no equivalent in ordered pairs.
y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.y = 5x + 1 is nota direct variation.
If a variable X is in inverse variation with a variable Y, then it is in direct variation with the variable (1/Y).
y=3x is a direct variation in that y varies directly with x by a factor of 3. Any linear equation (a polynomial of degree 1, which is a polynomial equation with a highest exponent of 1), is a direct variation of y to x by some constant, and this constant is simply the coefficient of the "x" term. Other examples: y=(1/2)x is a direct variation, and the constant of variation is 1/2 y=-9x is a direct variation, and the constant of variation is -9
1
No.
No, direct variation is "y=ax." In direct variation a equals any real constant, b=1, and c must equal zero. If any of thee conditions are changed, it is not direct variation.
There is only one equation that is given in the question and that equation is not a direct variation.
The answer is 1
1
If there are n numbers in the group, there aren2 ordered pairs if the numbers can be repeated,n*(n-1) ordered pairs if the numbers cannot be repeated,n2/2 pairs if the numbers can be repeated,n*(n-1)/2 pairs if the numbers cannot be repeated.