No, because the biggest length (hypotenuse) has to be equal to the square root of the sum of the squares of the other two sides, which it is not
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A triangle with side a: 5, side b: 8, and side c: 11 units has an area of 18.33 square units.This is not a right triangle, so it has to be calculated as two smaller right triangles, or using Heron's Formula since the side lengths are known.Here p= half-perimeter = (5 + 8 +11)/2 =12A = sqrt {p [(p - a) * (p - b) * (p - c)]}A = sqrt [ 12 (7 x 4 x 1)]A = sqrt [12 x 28]A = sqrt 336 = about 18.33
The longest side can have a length of 6, 8, or 10 units. It cannot have an odd length. If the third side has to be the longest, the two shorter sides can only have integer lengths of 1 and 2 2 and 3 3 and 4
Half the length of one side multiplied by (square root of 3)/(2). in triangle ABC with height H: (A•sqrt3)/2 or A (sqrt3)/2 This is because of the Pythagorean theorem. You draw a line from the top vertex of the triangle vertically to the bottom side. This line is perpendicular to the bottom side and it will bisect that side. Now you want to know the length of your new line. On each side of it, you have a smaller triangle, one side with the length of the side of the original triangle (let's call it s) and one side with length half that, (1/2)s. Since the side with length s will be the hypotenuse of the triangle, we know s2 = (s/2)2 + h2 by the Pythagorean theorem. (h stands for height.) s2 = s2/4 + h2 s2 (1-1/4) =h2 s2(3/4) =h2 (sqrt3)s/2 = h
The slope for a 45 degree slope triangle is 1/1 because the slope triangle is an isosceles right triangle.