If you mean 9x^2-24x+16 then yes it can because its discriminant is equal to zero and it is (3x-4)(3x-4) when factored
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The idea is to take out perfect squares. The largest perfect square in this case is 256, which is the square of 16 (if you have trouble figuring this out, you can take out a smaller perfect square first, and then see if you find additional perfect squares). In any case, the end result should not have a factor that is a perfect square. Using the symbol "root()" for square root: root(512) = root(256 x 2) = root(256) x root(2) = 16 root(2)
No; you can prove the square root of any positive number that's not a perfect square is irrational, using a similar method to showing the square root of 2 is irrational.
First note that 84=4x21 and 4 is a perfect square. So square root of (84)=square root (4x21)=Square root (4) Square root (21)= 2 multiplied by the square root of 21. You can also write this using rational exponents, but this is not in radical form. It is an equivalent expression, however. 2 x (21)1/2
the form of an expression compossed of products of factors, rather than sums or differences of terms. the expressions x(x-2) and (x+3)(x+4) are in factored form. y=(x-2)(x+5), or factored form, is an equation that describes a parabola. Once factored, using a FOIL method, it becomes standard form. y=(x-2)(x+5) y=x^2+5x-2x-10 y=x^2+3x-10
The square root of 900 is 30 and it is a factor of 900