0
(100 - 100 / 100 - 100) = 2
=> 102 - 102 / 10(10 - 10) =2
=> (10 + 10) (10 - 10) / 10(10 - 10) = 2 [a2 - b2 = (a + b) (a - b)]
Cancelling ( 10 - 10 ) {numerator} from ( 10 - 10 ) {denominator}
=> ( 10 + 10 ) / 10 = 2
=> 20 / 10 = 2
=> 2 = 2 [Hence, Proved]
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