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(100 - 100 / 100 - 100) = 2

=> 102 - 102 / 10(10 - 10) =2

=> (10 + 10) (10 - 10) / 10(10 - 10) = 2 [a2 - b2 = (a + b) (a - b)]

Cancelling ( 10 - 10 ) {numerator} from ( 10 - 10 ) {denominator}

=> ( 10 + 10 ) / 10 = 2

=> 20 / 10 = 2

=> 2 = 2 [Hence, Proved]

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Q: Can Anyone Prove 100 minus 100 divided by 100 minus 100 equals 2?
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