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No, because you should be able to add up any two side lengths and their sum should be greater than the third side length. 38 + 29 is not greater than 73.

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Q: Can a triangle have side lengths 38 inches 73 inches and 29 inches?
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Triangle with sides of lengths 20 21 and 29 is a right triangle true or false?

TRUE


How do you know if a triangle is a right triangle using the pythagorean therom?

We know that a right triangle is a triangle having a right angle, where the side opposite the right angle is the hypotenuse, and the perpendicular sides are the legs of the right triangle. The Pythagorean theorem gives the relationship between the lengths of the sides of a right triangles. In the case where you know only the measure lengths of the sides of a triangle, you need to test these measures. If one of the sides of the triangle has a square measure equal to the sum of the square measures of two other sides, then this side is called the hypotenuse and opposite to this side is a 90 degree angle, which is a right angle. So, you can say that this triangle is a right triangle. Pythagorean triple are very helpful to determine a right triangle, such as: (3, 4, 5), (5,12,13), (8, 15, 17), (7, 24, 25), and (20, 21, 29).


What is the perimeter of an isosceles triangle with a base of 29 and a side of 81?

Perimeter = 81+81+29 = 191 units of measurement


Area of triangle 12Cm 7Cm 10Cm?

To find the area of a triangle with side lengths 12 cm, 7 cm, and 10 cm, we can use Heron's formula. First, calculate the semi-perimeter of the triangle by adding the three side lengths and dividing by 2: (12 + 7 + 10) / 2 = 29/2 = 14.5 cm. Then, use Heron's formula: Area = √[s(s-a)(s-b)(s-c)], where s is the semi-perimeter and a, b, and c are the side lengths. Plugging in the values, we get Area = √[14.5(14.5-12)(14.5-7)(14.5-10)] = √[14.52.57.5*4.5] = √2446.25 ≈ 49.46 cm².


What is the square root of 29?

√29 ≈ ± 5.385165This is what the answer would be using the Pythagorean Theorem to calculate the length of the hypotenuse for a right triangle described with 2 sides of 5 and 2 units each.A2 + B2 = C252 + 22 = C225 + 4 = C229 = C2C=√29