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To find the area of a triangle with side lengths 12 cm, 7 cm, and 10 cm, we can use Heron's formula. First, calculate the semi-perimeter of the triangle by adding the three side lengths and dividing by 2: (12 + 7 + 10) / 2 = 29/2 = 14.5 cm. Then, use Heron's formula: Area = √[s(s-a)(s-b)(s-c)], where s is the semi-perimeter and a, b, and c are the side lengths. Plugging in the values, we get Area = √[14.5(14.5-12)(14.5-7)(14.5-10)] = √[14.52.57.5*4.5] = √2446.25 ≈ 49.46 cm².
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That is so wrong!
Let the three sides be a, b and c and let s = (a+b+c)/2
then area = sqrt[s*(s-a)*(s-b)*(s-c)]
So here s = 14.5 cm and so area = sqrt(14.5*2.5*7.5*4.5) = sqrt(1223.4375)
= 34.98 sq cm (to 2 dp)
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Is a 5cm by 12cm a right triangle?
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Area 51.
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What is the perimeter of 7cm by 6cm?
Assuming that this is a rectangle, you know that the length (longer side) would be 7cm, and the width (shorter side) would be 6cm. The formula for perimeter is, 2(length) + 2(width) = Perimeter Now we can plug in our numbers, 2(7cm) + 2(6cm) = 14cm + 12cm = 26cm The perimeter would be 26cm, assuming that this is a rectangle ^^
