To find the area of a triangle with side lengths 12 cm, 7 cm, and 10 cm, we can use Heron's formula. First, calculate the semi-perimeter of the triangle by adding the three side lengths and dividing by 2: (12 + 7 + 10) / 2 = 29/2 = 14.5 cm. Then, use Heron's formula: Area = √[s(s-a)(s-b)(s-c)], where s is the semi-perimeter and a, b, and c are the side lengths. Plugging in the values, we get Area = √[14.5(14.5-12)(14.5-7)(14.5-10)] = √[14.52.57.5*4.5] = √2446.25 ≈ 49.46 cm².
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That is so wrong!
Let the three sides be a, b and c and let s = (a+b+c)/2
then area = sqrt[s*(s-a)*(s-b)*(s-c)]
So here s = 14.5 cm and so area = sqrt(14.5*2.5*7.5*4.5) = sqrt(1223.4375)
= 34.98 sq cm (to 2 dp)
If two sides of a triangle have lengths of 5cm and 12cm, then the third side can have any length that's more than 7cm and less than 17cm. If the third side is 13cm, then the triangle is a right triangle.
Area 51.
The formula to calculate the area of a triangle is 1/2 * base * height. In this case, the base is 12 cm and the height is 7 cm. Plugging these values into the formula, we get 1/2 * 12 cm * 7 cm = 42 square cm. Therefore, the area of the triangle is 42 square cm.
A triangle with side a: 7, side b: 7, and side c: 5 cm has an area of 16.35 square cm.
Assuming that this is a rectangle, you know that the length (longer side) would be 7cm, and the width (shorter side) would be 6cm. The formula for perimeter is, 2(length) + 2(width) = Perimeter Now we can plug in our numbers, 2(7cm) + 2(6cm) = 14cm + 12cm = 26cm The perimeter would be 26cm, assuming that this is a rectangle ^^