To find the area of a triangle with side lengths 12 cm, 7 cm, and 10 cm, we can use Heron's formula. First, calculate the semi-perimeter of the triangle by adding the three side lengths and dividing by 2: (12 + 7 + 10) / 2 = 29/2 = 14.5 cm. Then, use Heron's formula: Area = √[s(s-a)(s-b)(s-c)], where s is the semi-perimeter and a, b, and c are the side lengths. Plugging in the values, we get Area = √[14.5(14.5-12)(14.5-7)(14.5-10)] = √[14.52.57.5*4.5] = √2446.25 ≈ 49.46 cm².
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That is so wrong!
Let the three sides be a, b and c and let s = (a+b+c)/2
then area = sqrt[s*(s-a)*(s-b)*(s-c)]
So here s = 14.5 cm and so area = sqrt(14.5*2.5*7.5*4.5) = sqrt(1223.4375)
= 34.98 sq cm (to 2 dp)
If two sides of a triangle have lengths of 5cm and 12cm, then the third side can have any length that's more than 7cm and less than 17cm. If the third side is 13cm, then the triangle is a right triangle.
Area 51.
The formula to calculate the area of a triangle is 1/2 * base * height. In this case, the base is 12 cm and the height is 7 cm. Plugging these values into the formula, we get 1/2 * 12 cm * 7 cm = 42 square cm. Therefore, the area of the triangle is 42 square cm.
A triangle with side a: 7, side b: 7, and side c: 5 cm has an area of 16.35 square cm.
Assuming that this is a rectangle, you know that the length (longer side) would be 7cm, and the width (shorter side) would be 6cm. The formula for perimeter is, 2(length) + 2(width) = Perimeter Now we can plug in our numbers, 2(7cm) + 2(6cm) = 14cm + 12cm = 26cm The perimeter would be 26cm, assuming that this is a rectangle ^^
10cm x 7cm x 12cm =840 square cm3
If two sides of a triangle have lengths of 5cm and 12cm, then the third side can have any length that's more than 7cm and less than 17cm. If the third side is 13cm, then the triangle is a right triangle.
if it is a scalene triangle yes scalene triangle have no congruent sides and angles
70 square cm.
The area of triangle is : 42.0
Two sides of a triangle are not sufficient to determine its area.
The perimeter of a shape is the sum of the lengths of all its sides. In this case, the shape is a rectangle with sides measuring 7cm and 10cm. To find the perimeter, you add up all the sides: 7cm + 7cm + 10cm + 10cm = 34cm. Therefore, the perimeter of this shape is 34cm.
Area 51.
To calculate the area of a triangle with side lengths of 11cm, 8cm, and 7cm, we first need to determine the semi-perimeter of the triangle. The semi-perimeter (s) is calculated by adding all three sides together and dividing by 2, so s = (11 + 8 + 7) / 2 = 13 cm. Next, we can use Heron's formula to find the area of the triangle, which is given by the formula: Area = √[s(s-a)(s-b)(s-c)], where a, b, and c are the side lengths. Plugging in the values, we get Area = √[13(13-11)(13-8)(13-7)] = √[1325*6] = √780 ≈ 27.93 cm².
No because the sum of the smaller sides must be greater than the longest side
To find the area of a triangle, you can use the formula: Area = 0.5 * base * height. In this case, the base is 5cm and the height is 7cm. Plugging these values into the formula, we get Area = 0.5 * 5cm * 7cm = 17.5 square centimeters. Therefore, the area of the triangle is 17.5 square centimeters.
The height has not been given but the area of the triangle is: 0.5*height*base