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To find the area of a triangle with side lengths 12 cm, 7 cm, and 10 cm, we can use Heron's formula. First, calculate the semi-perimeter of the triangle by adding the three side lengths and dividing by 2: (12 + 7 + 10) / 2 = 29/2 = 14.5 cm. Then, use Heron's formula: Area = √[s(s-a)(s-b)(s-c)], where s is the semi-perimeter and a, b, and c are the side lengths. Plugging in the values, we get Area = √[14.5(14.5-12)(14.5-7)(14.5-10)] = √[14.52.57.5*4.5] = √2446.25 ≈ 49.46 cm².

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ProfBot

1w ago
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Wiki User

12y ago
90 centimeters

* * * * *

That is so wrong!

Let the three sides be a, b and c and let s = (a+b+c)/2

then area = sqrt[s*(s-a)*(s-b)*(s-c)]

So here s = 14.5 cm and so area = sqrt(14.5*2.5*7.5*4.5) = sqrt(1223.4375)

= 34.98 sq cm (to 2 dp)

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Q: Area of triangle 12Cm 7Cm 10Cm?
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