Yes - the altitude of an equilateral triangle is perpendicular to the side chosen as the base and bisects that side and the opposite angle.
Also, the altitude of an isosceles triangle when measured from the third side (the side that is not equal to the other two sides) is a perpendicular bisector of the base and also bisects the opposite angle.
Biconditional Statement for: Perpendicular Bisector Theorem: A point is equidistant if and only if the point is on the perpendicular bisector of a segment. Converse of the Perpendicular Bisector Theorem: A point is on the perpendicular bisector of the segment if and only if the point is equidistant from the endpoints of a segment.
The Perpendicular bisector concurrency conjecture is the circumcenter
The perpendicular bisector of a line segment AB is the straight line perpendicular to AB through the midpoint of AB.
Equilateral triangles
Perpendicular Bisector
No.
Yes.
No, the perpendicular bisector of a side of a triangle does not necessarily pass through the opposite vertex. The perpendicular bisector is a line that is perpendicular to a segment at its midpoint, and it may intersect the interior or exterior of the triangle, depending on its shape. In fact, the only time a perpendicular bisector passes through the opposite vertex is in the case of an isosceles triangle, where the two sides are equal, and their perpendicular bisectors coincide with the altitude.
Yes, provided that the base is not one of the 2 equal sides. And it's also the perpendicular bisector of the base.
Yes. If you have an isosceles triangle standing up on the unequal side, thenthe line segment from the top vertex perpendicular to the base is all of these.
An angle bisector bisects an angle. A perpendicular bisector bisects a side.
A circle cannot form a perpendicular bisector.
on the perpendicular bisector
Biconditional Statement for: Perpendicular Bisector Theorem: A point is equidistant if and only if the point is on the perpendicular bisector of a segment. Converse of the Perpendicular Bisector Theorem: A point is on the perpendicular bisector of the segment if and only if the point is equidistant from the endpoints of a segment.
The Perpendicular bisector concurrency conjecture is the circumcenter
is parallel-apex
A circle cannot form a perpendicular bisector.