6x2 + 11x - 10 = (6x2 + 15x) - (4x + 10) = 3x(2x + 5) - 2(2x + 5) = (3x - 2)(2x + 5). Note, first, that the three co-efficients of the original quadratic expression are 6, 11, and -10. We need two numbers whose sum is 11 and whose product is (6)(-10) = -60. These two numbers turn out to be 15 and -4. Thus, we replace the middle term, 11x with 15x - 4x and proceed with the factorisation in the usual way.
4507 5267 - 500 - 200 - 60 = 4507
Thirty plus thiry
Factorize the LCM 20 = 2 x 2 x 5 Factorize the HCF 300 = 2 x 2x3x5x5 The HCF is the common factor for both numbers whereas the LCM contains all the unique factors of both numbers. So, 2 x 2x5 or 20 is a common factor for both numbers. The factors remaining are 3 and 5. So, 3 is a factor of one number and 5 is the factor of the second number. The first number = 20x 3 = 60 The second number = 20x 5 = 100 So 60 and 100 are two numbers Answer = 60 and 100
x = 10
6 + 11x - 60 =6 - 60 + 11x = -54 + 11x = 11x -54
-2(x + 5)(x - 6)
(x + 15)(x - 4)
It is: x2-16x+60 = (x-6)(x-10) when factored
360
60+60+60+60+60+60+60+60 =480 All the addition can happen in the same step. This is the same as 60*8.
300 !
60 + 60 + 60 + 50 + 50 + 40 + 30 = 350
The result of the equation - 130 plus 80 plus 60 plus 60, is found as follows;130 + 80 + 60 + 60= ( 130 + 80 ) + 60 + 60= 210 + ( 60 + 60 )= 210 + 120= 330Answer = 330
-30 plus 60 = 30
180
The result of the equation - 60 plus 90 plus 60 plus 80, is found as follows; 60 + 90 + 60 + 80 = ( 60 + 90 ) + 60 + 80 = 150 + ( 60 + 80 ) = 150 + 140 = 290 Answer = 290