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6x2 + 11x - 10 = (6x2 + 15x) - (4x + 10)
= 3x(2x + 5) - 2(2x + 5)
= (3x - 2)(2x + 5).
Note, first, that the three co-efficients of the original quadratic expression are 6, 11, and -10.
We need two numbers whose sum is 11 and
whose product is (6)(-10) = -60.
These two numbers turn out to be 15 and -4.
Thus, we replace the middle term, 11x with 15x - 4x and proceed with the factorisation in the usual way.
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