The first sequence is f(n) = (3n + 2)2 . So the next number is 400.
The second sequence is f(n) = f(n - 1) + 6(sum of values 1 to (n - 1)) + 1, with f(0) = -10. So the next number is 333.
121, 144, 169, 196
1 4 9 16 25 36 49 64 81 100 121 144 169 196
The first 15 square numbers are 1, 4, 9, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225.
1, 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, 144, 169, 196, 225, 256, 289, 324, 361, 400...
96 + 4 = 100 96 + 25 = 121 96 + 100 = 196 96 + 529 = 625
100,96,196,292,488,780,1268,2048,3316,5364...
It is: 4/121
The are: 121 144 169 and 196
try 11 & 14. 11 + 14 = 25 11sqd = 121 14sqd = 196 196-121 = 75!!!
The first five square numbers greater than 100 are 121, 144, 169, 196, and 225.
121 and 196
300
121, 144, 169, and 196.
They are: 121 144 169 and 196
121, 144, 169, 196, 225, 256, 289, 324, and 361. 121 144 169 196 225 256 289 324 361
100 , 121 , 144, 169 , 196 and 225
By Pythagoras x2+ 92= 142So x2= 142- 92= 196 - 81 = 115therefore = x = sqrt(115) = 10.7 (approximately).By Pythagoras x2+ 92= 142So x2= 142- 92= 196 - 81 = 115therefore = x = sqrt(115) = 10.7 (approximately).By Pythagoras x2+ 92= 142So x2= 142- 92= 196 - 81 = 115therefore = x = sqrt(115) = 10.7 (approximately).By Pythagoras x2+ 92= 142So x2= 142- 92= 196 - 81 = 115therefore = x = sqrt(115) = 10.7 (approximately).