Yes. A well-known example is the function defined as:
f(x) =
* 1, if x is rational
* 0, if x is irrational
Since this function has infinitely many discontinuities in any interval (it is discontinuous in any point), it doesn't fulfill the conditions for a Riemann-integrable function. Please note that this function IS Lebesgue-integrable. Its Lebesgue-integral over the interval [0, 1], or in fact over any finite interval, is zero.
No it is NOT always bounded. Here is an example of an unbounded one. 1. 2x-y>-2 2. 4x+y
the zeros of a function is/are the values of the variables in the function that makes/make the function zero. for example: In f(x) = x2 -7x + 10, the zeros of the function are 2 and 5 because these will make the function zero.
You can tell if a function is even or odd by looking at its graph. If a function has rotational symmetry about the origin (meaning it can be rotated 180 degrees about the origin and remain the same function) it is an odd function. f(-x)=-f(x) An example of an odd function is the parent sine function: y=sinx If a function has symmetry about the y-axis (meaning it can be reflected across the y-axis to produce the same image) it is an even function. f(x)=f(-x) An example of an even function is the parent quadratic function: y=x2
You can tell if a function is even or odd by looking at its graph. If a function has rotational symmetry about the origin (meaning it can be rotated 180 degrees about the origin and remain the same function) it is an odd function. f(-x)=-f(x) An example of an odd function is the parent sine function: y=sinx If a function has symmetry about the y-axis (meaning it can be reflected across the y-axis to produce the same image) it is an even function. f(x)=f(-x) An example of an even function is the parent quadratic function: y=x2
the line that crosses through the origin
A function may have a finite number of discontinuities and still be integrable according to Riemann (i.e., the Riemann integral exists); it may even have a countable infinite number of discontinuities and still be integrable according to Lebesgue. Any function with a finite amount of discontinuities (that satisfies other requirements, such as being bounded) can serve as an example; an example of a specific function would be the function defined as: f(x) = 1, for x < 10 f(x) = 2, otherwise
How about f(x) = floor(x)? (On, say, [0,1].) It's monotone and therefore of bounded variation, but is not Lipschitz continuous (or even continuous).
((-1)^n)
I believe the maximum would be two - one when the independent variable tends toward minus infinity, and one when it tends toward plus infinity. Unbounded functions can have lots of asymptotes; for example the periodic tangent function.
A function whose upper bound would have attained its upper limit at a bound. For example, f(x) = x - a whose domain is a < x < b The upper bound is upper bound is b - a but, because x < b, the bound is never actually attained.
Big O notation (also O()) describes the limiting behaviour of a function when the argument tends towards a particular value (most often we consider infinity) usually in terms of simpler functions. For example, the statement : ; would imply that the function T has n2 time complexity - that is, it is upper bounded by the function n2.
If the distribution is discrete you need to add together the probabilities of all the values between the two given ones, whereas if the distribution is continuous you will need to integrate the probability distribution function (pdf) between those limits. The above process may require you to use numerical methods if the distribution is not readily integrable. For example, the Gaussian (Normal) distribution is one of the most common continuous pdfs, but it is not analytically integrable. You will need to work with tables that have been computed using numerical methods.
When you integrate by parts, you generally want to select part of a function that can be differentiated easily (and also, simplifiable), and the rest of it be easily integrable. For example, the integral of x2sin(x) dx is quite simple since we can choose u = x2 --> du = 2xdx, and dv = sin(x)dx, v = -cos(x), and go on from there. However this would require applying parts twice.
it is a data that is bounded. Example of control that bound data is GridView and DetailsView.
No it is NOT always bounded. Here is an example of an unbounded one. 1. 2x-y>-2 2. 4x+y
Bounded motion refers to the movement of an object within a limited range or set boundaries. In physics, it often relates to oscillatory or periodic motion where the object's displacement or velocity is confined to a certain region. An example of bounded motion is a pendulum swinging back and forth within a specific angle.
A function call is where you "call" a function and execute its body. For example: void example() { } int main() { example(); // call the function "example" and execute its bodyreturn 0; }