Yes, you can do 12 + 7 + 5 = 24
You can arrange them to make a cube.12 edges, 6 faces.
Make up a data set of at least 12 numbers that have the following landmarks maxium:18 range 13 mode 7 median 12
There are no such numbers. The only two numbers that sum to 12 and whose product is -84 are irrational, and so cannot be considered as factors of 84.
12 and 1
The bottoms number like 3/4 4 would be the denominator heres a problem 6/12 + 2/12 the bottom numbers are the same
Assuming that the only permitted operation is addition, then there are 4 combinations.
5 + 7 + (6 x √4) = 12 + (6 x 2) = 12 + 12 = 24
12+5+5+1
One example. 12*8+3+7-6 = 100 The key is finding sets of 10s
7+5=12 2-9=3 3x3=9
(5+7)*(5-3)=12*2=24
No. By adding 4+4+4 the answer comes to 12. To subtract the answer comes to 4. By multiplying it is 64.
2x2x3 = 12
(5-2)*4 = 12
You cannot! Answer dated: 13 January 2012
Impossible, as there are not enough numbers to cover all squares.
You can make 4*3*2/2 = 12 numbers.