You can arrange them to make a cube.12 edges, 6 faces.
There are no such numbers. The only two numbers that sum to 12 and whose product is -84 are irrational, and so cannot be considered as factors of 84.
12 and 1
Well, honey, if you want a set of numbers that fit those criteria, how about 7, 7, 7, 12, 12, 12, 12, 12, 12, 12, 18, 18? You've got your mode of 7, median of 12, maximum of 18, and a range of 13. Looks like I just served you a math cocktail with a side of sass. Cheers!
The bottoms number like 3/4 4 would be the denominator heres a problem 6/12 + 2/12 the bottom numbers are the same
To find the number of combinations to make 40 using the numbers 12 and 4, we can use a mathematical approach. Since we are looking for combinations, not permutations, we need to consider both the order and repetition of the numbers. One way to approach this is by using a recursive formula or dynamic programming to systematically calculate the combinations. Another approach is to use generating functions to represent the problem and then find the coefficient of the term corresponding to 40 in the expansion of the generating function. Both methods require a deep understanding of combinatorics and mathematical algorithms to accurately determine the number of combinations.
5 + 7 + (6 x √4) = 12 + (6 x 2) = 12 + 12 = 24
12+5+5+1
One example. 12*8+3+7-6 = 100 The key is finding sets of 10s
7+5=12 2-9=3 3x3=9
(5+7)*(5-3)=12*2=24
No. By adding 4+4+4 the answer comes to 12. To subtract the answer comes to 4. By multiplying it is 64.
(5-2)*4 = 12
2x2x3 = 12
You cannot! Answer dated: 13 January 2012
Impossible, as there are not enough numbers to cover all squares.
You can make 4*3*2/2 = 12 numbers.