You can make twelve using three different numbers by adding 1, 4, and 7 together: 1 + 4 + 7 = 12. Another combination could be 2, 3, and 7: 2 + 3 + 7 = 12. You can also use 3, 4, and 5: 3 + 4 + 5 = 12.
24
Three possible English expressions for (12y) are: "twelve times y," "the product of twelve and y," and "twelve multiplied by y." Each expression conveys the same mathematical relationship using different phrasing.
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
Two almost perfect numbers between five and twenty are six and twelve. Six has divisors one, two, and three, which add up to five, just one less than itself. Twelve has divisors one, two, three, four, and six, summing to sixteen, which is four less than twelve. Both numbers are close to being perfect, as they fall short by a small amount.
No 5291 is not a prime using 2 numbers. It is a prime using three numbers.
1000
24
Three possible English expressions for (12y) are: "twelve times y," "the product of twelve and y," and "twelve multiplied by y." Each expression conveys the same mathematical relationship using different phrasing.
You can select 9 numbers for the first digit, 8 numbers for the second digit, and 7numbers for the third digit; so 504 (e.g. 9*8*7) different three digit numbers can be written using the digits 1 through 9.
Two almost perfect numbers between five and twenty are six and twelve. Six has divisors one, two, and three, which add up to five, just one less than itself. Twelve has divisors one, two, three, four, and six, summing to sixteen, which is four less than twelve. Both numbers are close to being perfect, as they fall short by a small amount.
No 5291 is not a prime using 2 numbers. It is a prime using three numbers.
There are 3*2*1 = 6 of them.
89,999 different numbers i guess
If you are using three distinct numbers and want to find the number of different combinations that can be formed, you would consider the combinations of those numbers. For three numbers, the combinations can be represented as C(3, k) for k = 1 to 3. Thus, the total combinations are 3 (for k=1) + 3 (for k=2) + 1 (for k=3), resulting in a total of 7 unique combinations.
6 possible 3 digit combonations
81 As there are no limits stated then you can have a number comprising a repeated single digit (such as 2222), two pairs of numbers (e.g. 2244) or three different numbers (such as 2462). The first digit can be one of any of the 3 numbers. The second digit can be one of any of the three numbers, as can the third digit and also the fourth. Then you can have 3 x 3 x 3 x 3 = 81 different 4-digit numbers using the three given numbers.
Using 1, 2, and 3, you can make 27 whole numbers.