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Construct a truth table for ~q (p q)

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13y ago

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Construct a Truth Table for the statement NOT p - p?

Making a truth table is actually very simple.For the statement P, it can either be true, or false.P--TFNOT P, or -p (or ~p) is the opposite. If P is true, then not P is... false!The same holds true for if P is false, what is not P? True!The truth table for ~p looks like thisP | ~p--------T | FF | T


How do you construct a truth table for or p or q?

___p_|_t_|_f_| q__t_|_t_|_t_| ___f_|_t_|_f_|


what is the correct truth table for p V -q?

what is the correct truth table for p V~ q


Difference between excitation table and truth table?

truth table gives relation between i/p & o/p. excitation table is use for design of ff & counters.


How do you construct a truth table for parenthesis not p q parenthesis if and only if p?

Assuming that you mean not (p or q) if and only if P ~(PVQ)--> P so now construct a truth table, (just place it vertical since i cannot place it vertical through here.) P True True False False Q True False True False (PVQ) True True True False ~(PVQ) False False False True ~(PVQ)-->P True True True False if it's ~(P^Q) -->P then it's, P True True False False Q True False True False (P^Q) True False False False ~(P^Q) False True True True ~(P^Q)-->P True True False False


what is the correct truth table for -p-> -q?

A+


Make a truth table for the statement if p then not q?

. p . . . . . q. 0 . . . . . 1. 1 . . . . . 0


How do you construct a truth table for q arrow p?

I guess you mean q → p (as in the logic operator: q implies p).To create this truth table, you run over all truth values for q and p (that is whether each statement is True or False) and calculate the value of the operator. You can use True/False, T/F, 1/0, √/X, etc as long as you are consistent for the symbol used for True and the symbol used for False (the first 3 suggestions given are the usual ones used).For implies:if you have a true statement, then it can only imply a true statement to be truebut a negative statement can imply either a true statement or a false one to be truegiving:. q . . p . q→p--------------. 0 . . 0 . . 1 .. 0 . . 1 . . 1 .. 1 . . 0 . . 0 .. 1 . . 1 . . 1 .


What is the proof of the modus ponens not by the truth table?

1)p->q 2)not p or q 3)p 4)not p and p or q 5)contrudiction or q 6)q


What is the truth table for p arrow q?

Not sure I can do a table here but: P True, Q True then P -> Q True P True, Q False then P -> Q False P False, Q True then P -> Q True P False, Q False then P -> Q True It is the same as not(P) OR Q


What is the truth table for negation p or negation q?

P Q (/P or /Q) T T F T F T F T T F F T


What is the truth table for p or q and the opposite of p and q?

P . . Q . . (P or Q)0 . . 0 . . . 00 . . 1 . . . 11 . . 0 . . . 11 . . 1 . . . 1=================P . . Q . . NOT(P and Q)0 . . 0 . . . . 10 . . 1 . . . . 11 . . 0 . . . . 11 . . 1 . . . . 0